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Brums [2.3K]
3 years ago
8

Particles in solids, liquids and gases move depending on how much energy they have.

Chemistry
2 answers:
7nadin3 [17]3 years ago
6 0
Answer: True

Increased temperature will result in the particles gaining kinetic energy btw. Therefore the more energy the particles have, the faster they move. Hope this helps! :)

In addition: A solid’s particles will always have less energy than a liquid or gas’s particles. So solid particles have the least amount of energy, liquid has the second most amount of energy and gases have the most amount of energy.
mylen [45]3 years ago
5 0

Answer:

A

Explanation:

they move to create more energy witch keeps them moving

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What mass of benzene is cooled from 83.8 °C to 77.1 °C when 167 J of energy is transferred out of the system? (The specific heat
dexar [7]

Answer:

14.32g

Explanation:

Initial temperature = 83.8°C

Final temperature = 77.1°C

Temperature change, ΔT = 83.8°C - 77.1°C = 6.7

Heat, H = 167J

Specific heat, c = 1.740J/g °C

m = ?

All these parameters are related with the equation below;

H = mcΔT

m = H / cΔT

m = 167 /  (1.740 * 6.7)

m = 167 / 11.658 = 14.32g

3 0
4 years ago
Preparation of Standard Buffer for Calibration of a pH Meter The glass electrode used in commercial pH meters gives an electrica
lana66690 [7]

Answer:

  • Mass of NaH₂PO₄·H₂O = 8.542 g
  • Mass of Na₂HPO₄ = 5.410 g

Explanation:

Keeping in mind the equilibrium:

H₂PO₄⁻ ↔ HPO₄⁻² + H⁺

We use the Henderson-Hasselbalch equation (H-H):

pH = pka + log\frac{[A^{-}]}{[HA]}

For this problem [A⁻] = [HPO₄⁻²] and [HA] = [H₂PO₄⁻]

From literature we know that pka = 7.21, from the problem we know that pH=7.00 and that

[HPO₄⁻²] + [H₂PO₄⁻] = 0.100 M

From this equation we can <u>express [H₂PO₄⁻] in terms of [HPO₄⁻²]</u>:

[H₂PO₄⁻] = 0.100 M - [HPO₄⁻²]

And then replace [H₂PO₄⁻] in the H-H equation, <u>in order to calculate [HPO₄⁻²]</u>:

7.00=7.21+log\frac{[HPO4^{-2}] }{0.100 M-[HPO4^{-2}]} \\-0.21=log\frac{[HPO4^{-2}] }{0.100 M-[HPO4^{-2}]}\\10^{-0.21} =\frac{[HPO4^{-2}] }{0.100 M-[HPO4^{-2}]}\\0.616*(0.100M-[HPO4^{-2}])=[HPO4^{-2}]\\0.0616 M = 1.616*[HPO4^{-2}]\\0.03812 M =[HPO4^{-2}]

With the value of  [H₂PO₄⁻],<u> we calculate [HPO₄⁻²]</u>:

[HPO₄⁻²] + 0.0381 M = 0.100 M

[HPO₄⁻²] = 0.0619 M

Finally, using the concentrations, the volume, and the molecular weights; we can calculate the weight of each substance:

  • Mass of NaH₂PO₄·H₂O = 0.0619 M * 1 L * 138 g/mol = 8.542 g
  • Mass of Na₂HPO₄ = 0.0381 M * 1 L * 142 g/mol = 5.410 g

8 0
4 years ago
The prefix centi- means
olya-2409 [2.1K]

100. Centi means a hundred.

5 0
3 years ago
Read 2 more answers
I am a subatomic particle <br> that is positively charged what am I?
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6 0
3 years ago
The pressure of a sample of helium in a 1.00-L container is 0.988 atm. What is the new pressure if the sample is placed in a 2.0
Vikentia [17]

Answer : The new pressure if the sample placed in a 2.00-L container is, 0.494 atm.

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 0.988 atm

P_2 = final pressure = ?

V_1 = initial volume = 1.00 L

V_2 = final volume = 2.00 L

Now put all the given values in the above equation, we get:

0.988atm\times 1.00L=P_2\times 2.00L

P_2=0.494atm

Thus, the new pressure if the sample placed in a 2.00-L container is, 0.494 atm.

4 0
4 years ago
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