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lord [1]
3 years ago
11

A slide projector has a magnification of 50. How wide will the projected image be if the slide is 2.8 cm wide?

Physics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

hi = 12mm or 1.2cm

Explanation:

XOXO

Kit ^w^

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How can you decrease the amount of input force of a wheel and axle?
nasty-shy [4]

Explanation:

hmm by the increasing the size of wheel and decreasing axle

7 0
3 years ago
In a long straight wire, what current is required to exert a 1.0μN force on a 1.0μC charge moving at 1.5×106m/s parallel to the
Bas_tet [7]

Answer:

Current in the wire is given as

i = 1.17 \times 10^{-7} A

Explanation:

magnetic field due to long current carrying wire is given as

B = \frac{\mu_0 i}{2\pi r}

so we have magnetic force on moving charge is given as

F = qvB

so we have

F = (1\times 10^{-6})(1.5 \times 10^6)(\frac{\mu_0 i}{2\pi (0.35)})

so we have

1\times 10^{-6} = 1.5 \times \frac{2 i}{0.35}

i = 1.17 \times 10^{-7} A

6 0
3 years ago
A bug of mass 2.2 g is sitting at the edge of a cd of radius 3.0 cm. if the cd is spinning at 280 rpm, what is the angular momen
m_a_m_a [10]
M = 2.2 g = 2.2 x 10⁻³ kg, the mass of the bug.
r = 3.0 cm = 0.03 m, the radial distance from the center.

The angular speed is
ω = 280 rpm
    = (280 rev/min)*(2π rad/rev)*(1/60 min/s)
    = 29.3215 rad/s

The moment of inertia of the bug is
I = mr²
  = (2.2 x 10⁻³ kg)*(0.03 m)²
  = 1.98 x 10⁻⁶ kg-m²

Calculate the angular momentum of the bug.
J = Iω
  = (1.98 x 10⁻⁶ kg-m²)*(29.3215 rad/s)
  = 5.806 x 10⁻⁵ (kg-m²)/s

Answer: 5.806 x 10⁻⁵ (kg-m²)/s

5 0
4 years ago
Two particles of masses m and 3m are moving toward each other along the x-axis with the same speed v. They undergo a head- on el
astra-53 [7]

Answer:0

Explanation:

Given

two particles of mass m and 3m

They  move towards each other with velocity v

As the collision is Elastic therefore value of coefficient of restitution is 1

e=1

e=\frac{Relative\ speed\ after\ collision}{Relative\ speed\ before\ collision}

if u_1 and u_2 are velocity of approach of m and 3 m

and v_1 and v_2 are velocity after collision respectively

therefore

v_2-v-1=u_1-u_2

v_2-v_1=v-(-v)

v_2-v_1=2 v

conserving momentum

m\cdot v+3m\cdot (-v)=3m\cdot (v_2)+m\cdot v_1

-2mv=3mv_2+m(v_2-2v)

4mv_2=0

v_2=0

Therefore velocity of heavier mass is zero

 

8 0
3 years ago
Read 2 more answers
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A pair of scissors .....................................
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