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3 years ago

In ionic compounds which group from the periodic table usually provide anion?

Physics

1 answer:

koban [17]3 years ago

3 0

Pretty sure it’s halogens , or groups 14-17

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Una partícula se mueve en el plano XY efectúa un desplazamiento mientras actúa sobre ella una fuerza constante. X= (4i + 3j) m,

dsp73

Answer:

a) La magnitud del desplazamiento es de 5 m

La magnitud de la fuerza es 20 N

b) El trabajo realizado por la fuerza es de 100 J

c) El ángulo entre la fuerza y el plano es 0 °

Explanation:

a) La magnitud del desplazamiento se encuentra por la relación;

$\left | X \right | = \sqrt{X_{x}^{2}+X_{y}^{2}}$

Lo que da;

$\left | X \right | = \sqrt{4^{2}+3^{2}} = 5 \ m$

De manera similar, la magnitud de la fuerza, F, se encuentra como sigue;

$\left | F \right | = \sqrt{F_{x}^{2}+F_{y}^{2}}$

Lo que da;

$\left | F \right | = \sqrt{16^{2}+12^{2}} = 20 \ N$

b) El trabajo, W, realizado por la fuerza = Fuerza, F × Distancia, X

∴ Ancho = 20 N × 5 m = 100 N · m = 100 J

c) La dirección de la fuerza viene dada por la siguiente fórmula;

$tan^{-1} \left (\dfrac{F_y}{F_x} \right ) = tan^{-1} \left (\dfrac{12}{16} \right ) = 38.9^{\circ}$

La dirección del plano viene dada por la siguiente fórmula;

$tan^{-1} \left (\dfrac{X_y}{X_x} \right ) = tan^{-1} \left (\dfrac{3}{4} \right ) = 38.9^{\circ}$

Por tanto, el ángulo entre la fuerza y el plano = 0 °

La fuerza actúa a lo largo del plano.

6 0

3 years ago

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photoshop1234 [79]

Your answer would be A):Organize a laboratory in Germany.

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3 years ago

Select all that apply. An acorn falls from a tree. Which of the following statements is true? The force of gravity is acting on

DedPeter [7]

The net force on the acorn is less than the force of gravity.

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4 years ago

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Sophie throws a tennis ball down from a height of 1.5 m at an angle of 450 with respect to vertical. She drops another tennis ba

Katena32 [7]

Given that,

Height =1.5 m

Angle = 45°

We need to find the greater speed of the ball

Using conservation of energy

$P.E_{i}+K.E_{f}=P.E_{f}+K.E_{f}$

$mgh+\dfrac{1}{2}mv_{i}^2=mgh+\dfrac{1}{2}mv_{f}^2$

Here, initial velocity and final potential energy is zero.

$mgh=\dfrac{1}{2}mv_{f}^2$

Put the value into the formula

$9.8\times1.5=\dfrac{1}{2}v_{f}^2$

$v_{f}^2=2\times9.8\times1.5$

$v_{f}=\sqrt{2\times9.8\times1.5}$

$v_{f}=5.42\ m/s$

Hence, the greater speed of the ball is 5.42 m/s.

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3 years ago

A car engine burns fuel and has moving parts. Sometimes, an engine can become too hot and overheat. What can prevent the engine

arsen [322]

there many things you could do, one is try getting a cooling system, another thing is its extramly hot and you may need to tunr off your car to prevent the engine from over heating.

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4 years ago

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