The following scenarios are pertinent to driving conditions that one may encounter. See the following rules of driving.
<h3>What do you do when the car is forced into the guardrail?</h3>
Best response:
- I'll keep my hands on the wheel and slow down gradually.
- The reason I keep my hands on the steering wheel is to avoid losing control.
- This will allow me to slowly back away from the guard rail.
- The next phase is to gradually return to the fast lane.
- Slamming on the brakes at this moment would result in a collision with the car behind.
Scenario 2: When driving on a wet road and the car begins to slide
Best response:
- It is not advised to accelerate.
- Pumping the brakes is not recommended.
- Even lightly depressing and holding down the brake pedal is not recommended.
- The best thing to do is take one foot off the gas pedal.
- There should be no severe twists at this time.
Scenario 3: When you are in slow traffic and you hear the siren of an ambulance behind
Best response:
- The best thing to do at this moment is to go to the right side of the lane and come to a complete stop.
- This helps to keep the patient in the ambulance alive.
- It also provide a clear path for the ambulance.
- Moving to the left is NOT recommended.
- This will exacerbate the situation. If there is no place to park on the right shoulder of the road, it is preferable to stay in the lane.
Learn more about rules of driving. at;
brainly.com/question/8384066
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Answer:
Time taken = 136.32 minutes
Explanation:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
Answer:
w = 0.626 rad / s, v = 3.13 m/s
Explanation:
For this exercise let's use Newton's second law
F = m a
Where the force is a friction force and the acceleration is centripetal,
a = v² / r = w² r
The formula for friction force
fr = μ N
In a free body diagram
N- W = 0
W = N
The frictiμon outside goes from zero to the maximum value, let's calculate the speed for the maximum value of the friction force, replace
μ m g = m w² r
w = √ μ g / r
Let's calculate
w = √(0.2 9.8 / 5)
w = 0.626 rad / s
angular and linear velocity are related
v = w r
v = 0.626 5
v = 3.13 m/s
Technician a. Components should always look the same so they are known universally
Answer:
#include<iostream>
using namespace std;
int main()
{
double data[3][5],avg,least,most,total;
int leastNum,mostNum;
for(int i=0;i<3;i++)
{
cout<<"Enter quantity of food for monkey "<<i+1<<":\n";
for(int j=0;j<5;j++)
{
cout<<"Day "<<j+1<<": ";
cin>>data[i][j];
}
}
least = data[0][0];
most = data[0][0];
for(int i = 0;i<3;i++)
{
for(int j = 0;j<5;j++)
{
total+=data[i][j];
if(data[i][j]>most)
{
most=data[i][j];
mostNum=i+1;
}
if(data[i][j]<least)
{
least=data[i][j];
leastNum=i+1;
}
}
}
avg=total/5.0;
cout<<"Average food eaten in a day by all the 3 monkeys: "<<avg<<endl;
cout<<"Most amount of food eaten in a day: "<<most<<" by monkey: "<<mostNum<<endl;
cout<<"Least amount of food eaten in a day: "<<least<<" by monkey: "<<leastNum<<endl;
return 0;
}
