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Sidana [21]
3 years ago
7

A circuit contains a resistor, an inductor, and a capacitor. When an AC voltage is applied across the circuit, the impedance of

the circuit depends on the _______ of the voltage source.
Engineering
1 answer:
katen-ka-za [31]3 years ago
3 0

Answer:

The impedance of  the circuit depends on the angular frequency of the voltage source.

Explanation:

  • In a electric circuit, the magnitude of  the impedance, is given by the following expression:

       Z = \sqrt{R^{2} + (Xl-Xc)^{2} (1)

        where R = Resistance

                   Xl = Inductive reactance = ω*L

                   Xc = Capacitive Reactance = 1/ωC

        and  ω = angular frequency of the voltage source.

  • So, it can be seen that the impedance depends on the value of the constants R,L and C, and on the angular frequency ω.

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A thick aluminum block initially at 26.5°C is subjected to constant heat flux of 4000 W/m2 by an electric resistance heater whos
Yanka [14]

Given Information:

Initial temperature of aluminum block = 26.5°C

Heat flux = 4000 w/m²

Time = 2112 seconds

Time = 30 minutes = 30*60 = 1800 seconds

Required Information:

Rise in surface temperature = ?

Answer:

Rise in surface temperature = 8.6 °C after 2112 seconds

Rise in surface temperature = 8 °C after 30 minutes

Explanation:

The surface temperature of the aluminum block is given by

T_{surface} = T_{initial} + \frac{q}{k} \sqrt{\frac{4\alpha t}{\pi} }

Where q is the heat flux supplied to aluminum block, k is the conductivity of pure aluminum and α is the diffusivity of pure aluminum.

After t = 2112 sec:

T_{surface} = 26.5 + \frac{4000}{237} \sqrt{\frac{4(9.71\times 10^{-5}) (2112)}{\pi} }\\\\T_{surface} = 26.5 + \frac{4000}{237} (0.51098)\\\\T_{surface} = 26.5 + 8.6\\\\T_{surface} = 35.1\\\\

The rise in the surface temperature is

Rise = 35.1 - 26.5 = 8.6 °C

Therefore, the surface temperature of the block will rise by 8.6 °C after 2112 seconds.

After t = 30 mins:

T_{surface} = 26.5 + \frac{4000}{237} \sqrt{\frac{4(9.71\times 10^{-5}) (1800)}{\pi} }\\\\T_{surface} = 26.5 + \frac{4000}{237} (0.4717)\\\\T_{surface} = 26.5 + 7.96\\\\T_{surface} = 34.5\\\\

The rise in the surface temperature is

Rise = 34.5 - 26.5 = 8 °C

Therefore, the surface temperature of the block will rise by 8 °C after 30 minutes.

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Answer:

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