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2 years ago

A controlled process is described by the closed-loop transfer function G(s).

Engineering

1 answer:

MissTica2 years ago

3 0

Answer:

The answer is "Option B".

Explanation:

Given equation:

$G(s) =\frac{K(s + 1)}{2s^2 + (K-1)s + (K-1)}\\\\$

$\to 2s^2 + (K-1)s + (K-1)=0$

Calculating by the Routh's Hurwitz table:

$\to s^2 \ \ \ \ \ 2 \ \ \ \ \ \ K-1 \\\\\to s^2 \ \ \ \ \ K-1 \ \ \ \ \ \ \\\\\to s^0 \ \ ( \frac{(K-1)(K-1)(-2) (0)}{K-1} \\\\ \ \ \ \ = (K-1) )$

Form the above table:

$\to K-1 > 0 \\\\ \to K > 1$

In the above, the value of k is greater than 1.

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Calculate the convective heat-transfer coefficient for water flowing in a round pipe with an inner diameter of 3.0 cm. The water

olasank [31]

Answer:

h = 10,349.06 W/m^2 K

Explanation:

Given data:

Inner diameter = 3.0 cm

flow rate = 2 L/s

water temperature 30 degree celcius

$Q = A\times V$

$2\times 10^{-3} m^3 = \frac{\pi}{4} \times (3\times 10^{-2})^2 \times velocity$

$V = \frac{20\times 4}{9\times \pi} = 2.83 m/s$

$Re = \frac{\rho\times V\times D}{\mu}$

at 30 degree celcius $= \mu = 0.798\times 10^{-3}Pa-s , K = 0.6154$

$Re = \frac{10^3\times 2.83\times 3\times 10^{-2}}{0.798\times 10^{-3}}$

Re = 106390

So ,this is turbulent flow

$Nu = \frac{hL}{k} = 0.0029\times Re^{0.8}\times Pr^{0.3}$

$Pr= \frac{\mu Cp}{K} = \frac{0.798\times 10^{-3} \times 4180}{0.615} = 5.419$

$\frac{h\times 0.03}{0.615} = 0.0029\times (1.061\times 10^5)^{0.8}\times 5.419^{0.3}$

SOLVING FOR H

WE GET

h = 10,349.06 W/m^2 K

6 0

3 years ago

When the Challenger spacecraft exploded, which design step had not been thoroughly explored?

Llana [10]

Answer:

The escape systems not working

8 0

2 years ago

(Almost) FREE POINTS!!!!! Hey there, Im writting a research paper, and I want to know if you think NASA is a waste of money or n

tatuchka [14]

Answer:

No I don't think NASA is a waste of time. I don't think its a waste of time because NASA is exploring what is beyond Earth and its important to know about Space.

Explanation:

3 0

2 years ago

Read 2 more answers

A rectangular channel 3-m-wide carries 12 m^3/s at a depth of 90cm. Is the flow subcritical or supercritical? For the same flowr

hram777 [196]

Answer:

Super critical

1.2 m

Explanation:

Q = Flow rate = $12\ \text{m}^3/\text{s}$

w = Width = 3 m

d = Depth = 90 cm = 0.9 m

A = Area = wd

v = Velocity

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

$Q=Av\\\Rightarrow v=\dfrac{Q}{wd}\\\Rightarrow v=\dfrac{12}{3\times 0.9}\\\Rightarrow v=4.44\ \text{m/s}$

Froude number is given by

$Fr=\dfrac{v}{\sqrt{gd}}\\\Rightarrow Fr=\dfrac{4.44}{\sqrt{9.81\times 0.9}}\\\Rightarrow F_r=1.5$

Since $F_r>1$ the flow is super critical.

Flow is critical when $Fr=1$

Depth is given by

$d=(\dfrac{Q^2}{gw^2})^{\dfrac{1}{3}}\\\Rightarrow d=(\dfrac{12^2}{9.81\times 3^2})^{\dfrac{1}{3}}\\\Rightarrow d=1.2\ \text{m}$

The depth of the channel will be 1.2 m for critical flow.

4 0

2 years ago

Let’s define a new language called dog-ish. A word is in the lan- guage dog-ish if the word contains the letters ’d’, ’o’, ’g’ a

attashe74 [19]

Answer and Explanation:

// code

class Main {

public static void main(String[] args) {

* your code

System.out.println(inDogish("aplderogad"));

System.out.println(inXish("aplderogad", "dog"));

}

// returns true if the word is in dog-ish

// returns false if word is not in dog-ish

public static boolean inDogish(String word) {

// first find d

if (dogishHelper(word, 'd')) {

// first find string after d

String temp = word.substring(word.indexOf("d"));

// find o

if (dogishHelper(temp, 'o')) {

// find string after o

temp = temp.substring(temp.indexOf("o"));

// find g

if (dogishHelper(temp, 'g'))

return true;

}

The output is attached below

}

return false;

}

// necessary to implement inDogish recursively

public static boolean dogishHelper(String word, char letter) {

// end of string

if (word.length() == 0)

return false;

// letter found

if (word.charAt(0) == letter)

return true;

// search in next index

return dogishHelper(word.substring(1), letter);

}

// a generalized version of the inDogish method

public static boolean inXish(String word, String x) {

if (x.length() == 0)

return true;

if (word.length() == 0)

return false;

if (word.charAt(0) == x.charAt(0))

return inXish(word.substring(1), x.substring(1));

return inXish(word.substring(1), x.substring(0));

}

PS E:\fixer> java Main true true ne on

5 0

2 years ago