1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NemiM [27]
3 years ago
15

A controlled process is described by the closed-loop transfer function G(s).

Engineering
1 answer:
MissTica3 years ago
3 0

Answer:

The answer is "Option B".

Explanation:

Given equation:

G(s) =\frac{K(s + 1)}{2s^2 + (K-1)s + (K-1)}\\\\

if

\to 2s^2 + (K-1)s + (K-1)=0

Calculating by the Routh's Hurwitz table:

\to s^2  \ \ \ \ \    2  \ \ \ \ \ \  K-1 \\\\\to s^2  \ \ \ \ \    K-1  \ \ \ \ \ \   \\\\\to s^0 \ \  ( \frac{(K-1)(K-1)(-2) (0)}{K-1}  \\\\    \ \ \ \  = (K-1) )

Form the above table:

\to K-1 > 0 \\\\ \to K > 1

In the above, the value of k is greater than 1.

You might be interested in
A 50 mm diameter shaft is subjected to a static axial load of 160 kN. If the yield stress of the material is 350 MPa, the ultima
zvonat [6]

In order to develop this problem it is necessary to take into account the concepts related to fatigue and compression effort and Goodman equation, i.e, an equation that can be used to quantify the interaction of mean and alternating stresses on the fatigue life of a materia.

With the given data we can proceed to calculate the compression stress:

\sigma_c = \frac{P}{A}

\sigma_c = \frac{160*10^3}{\pi/4*0.05^2}

\sigma_c = 81.5MPa

Through Goodman's equations the combined effort by fatigue and compression is expressed as:

\frac{\sigma_a}{S_e}+\frac{\sigma_c}{\sigma_u}=\frac{1}{Fs}

Where,

\sigma_a=Fatigue limit for comined alternating and mean stress

S_e =Fatigue Limit

\sigma_c=Mean stress (due to static load)

\sigma_u = Ultimate tensile stress

Fs =Security Factor

We can replace the values and assume a security factor of 1, then

\frac{\sigma_a}{320}+\frac{81.5}{400}=\frac{1}{1}

Re-arrenge for \sigma_a

\sigma_a = 254.8Mpa

We know that the stress is representing as,

\sigma_a = \frac{M_c}{I}

Then,

Where M_c=Max Moment

I= Intertia

The inertia for this object is

I=\frac{\pi d^4}{64}

Then replacing and re-arrenge for M_c

M_c = \frac{\sigma_a*\pi*d^3}{32}

M_c = \frac{260.9*10^6*\pi*0.05^3}{32}

M_c = 3201.7N.m

Thereforethe moment that can be applied to this shaft so that fatigue does not occur is 3.2kNm

5 0
3 years ago
Are you?
Inessa [10]

Answer:

are you wht

didn't understand the question

6 0
2 years ago
Read 2 more answers
How do we find percentage error in measuring voltage across a resistor​
Black_prince [1.1K]

Answer:

  use the percentage error relation

Explanation:

The percentage error in anything is computed from ...

  %error = ((measured value)/(accurate value) -1) × 100%

__

The difficulty with voltage measurements is that the "accurate value" may be hard to determine. It can be computed from the nominal values of circuit components, but there is no guarantee that the components actually have those values.

Likewise, the measuring device may have errors. It may or may not be calibrated against some standard, but even measurement standards have some range of possible error.

6 0
3 years ago
Read 2 more answers
True or False? Early engineers used a trial-and­error approach, rather than mathematical and scientific principles when solving
yarga [219]

Answer:

<h2>True Most Especially in the field of Automotive Engineering</h2>

Explanation:

Normally, before the introduction of vehicle diagnostics when a vehicle, mostly automobile/car break down, one could be the vehicle mechanic would only suspect one or two related faults based on the present working condition of the car, the mechanic would perform some trial and error before he could fix the car.

But in recent times, the introduction of vehicle diagnostics devices and software has changed the order as vehicles can be connected to a computer that will scan and tell what   the problem is before a possible fix.

3 0
3 years ago
A spherical hot air balloon is initially filled with air having 120 kPa pressure and 24 °C temperature. Initial diameter of the
tino4ka555 [31]

Answer:

v = 1.076 m /s

Explanation:

Initial volume of balloon = 4/3 x  3.14 x (9.905/2)³

=508.56 m³

Final volume of balloon = 4/3 x 3.14 x (16.502/2)³

= 2351.73 m³

Increase in volume = 1843.17 m³

Cross sectional area of inlet  A  = 3.14 x( 1.458/2)²

A = 1.6687 m²

Volume rate of flow of air = cross sectional area x velocity of inflow

= 1 .6687 V [ V is velocity of inflow ]

Total time taken = Increase in volume / rate of flow of air

17.108 X 60 = 1843.17 / 1.6687 V

V = \frac{1843.17}{1.6687\times17.108\times60}

v = 1.076 m /s

8 0
3 years ago
Other questions:
  • How do I cancel my subscription
    12·2 answers
  • What is the difference between filler and electrode in Welding? Can a filler be an electrode? Can an electrode be a filler? Why?
    6·1 answer
  • How do you make a 3d print
    6·1 answer
  • A _______ contact allows current to flow when the switch's operator is not activated.?
    6·1 answer
  • Which basic principle influences how all HVACR systems work?
    14·1 answer
  • What is government role in the modern American version of capitalism
    11·1 answer
  • Which of the following is the class of ingredient which is the base for most baked items?
    5·1 answer
  • Identify the prefixes used in the International System of
    15·1 answer
  • How do you build a engine best anwser will get marked as brainlist
    7·1 answer
  • Can you help me with this
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!