Actual yield over theoretical yield, then multiply by 100
Answer:
9% solution by mass
Explanation:
If there is 500 gm of solution and 45 g of it is glucose then:
45/500 * 100% = 9 % solution
This was because the experiment showed that a substance could emit radiation even while it was not exposed to light.
The balanced chemical equation is given as:
2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)
We are given the yield of CH3CH2OCH2CH3 and the amount of ethanol to be used for the reaction. These values will be the starting point for the calculations.
Theoretical amount of product produced:
329 g CH3CH2OH ( 1 mol / 46.07 g ) ( 1 mol CH3CH2OCH2CH3 / 2 mol CH3CH2OH ) (74.12 g / mol ) = 264.66 g CH3CH2OCH2CH3
% yield = .775 = actual yield / 264.66
actual yield = 205.11 g CH3CH2OCH2CH3
