<span>1.) Adding CO2 creates a stress on the equlibrium system.which means there will be exothermic reaction in other words more product (i:e H2CO3) will be formed.
</span><span>The equilibrium will shift to the right to offset the applied stress.
</span>
Hence more H2CO3 will be produced. Option A is correct.
2.) Rate = <span>[SO2]2 x [O2] / [SO3]2.
</span>
Hence option C is correct.
Hope this helps!
Answer:
4.44 g Ne
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
0.220 mol Ne
<u>Step 2: Identify Conversions</u>
Molar Mass of Ne - 20.18 g/mol
<u>Step 3: Convert</u>
<u /> = 4.4396 g Ne
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
4.4396 g Ne ≈ 4.44 g Ne
Hello!
The hybridization of the C atom in CH₂Br₂ is sp3
When bonding, the orbitals "s" and "p" from C atoms interact to form hybridized orbitals. If the C atom has 4 sigma bonds, as is the case in CH₂Br₂, there are 4 hybridized orbitals required, so 1 "s" orbital and 3 "p" orbitals hybridize to form an sp3 hybrid orbital. This orbital has tetrahedral geometry and the bond angle is 109,5 °.
Have a nice day!
If you have an unknown value of c
and you bought c video games for r dollars so c is the independent variable because when you change it it changes the dependent variable<span />
Answer:
2.268 L
Explanation:
According to Ideal Gas Law, " The Volume of a given mass of gas is inversely proportional to the applied Pressure and directly proportional to applied temperature, ". Mathematically the initial and final states of gas are given as,
P₁ V₁ / T₁ = P₂ V₂ / T₂ ----------- (1)
Data Given;
P₁ = 0.998 atm
V₁ = 2.1 L
T₁ = 36 °C = 309 K
P₂ = 0.90 atm
T₂ = 28 °C = 301 K
V₂ = ??
Solving equation 1 for P₂,
V₂ = P₁ V₁ T₂ / T₁ P₂
Putting values,
V₂ = (0.998 atm × 2.1 L × 301 K) ÷ (309 K × 0.90 atm)
V₂ = 2.268 L