All categories

3 years ago

How can i tell on a position-time graph if it is speed or acceleration

1 answer:

6 0

You didn't say what "it" is.

On a position/time graph, the slope of the graph at any point is the speed
at that time.

If you want acceleration, then what you'd have to do is to measure the slope
at every point on the position/time graph, then use that information to draw
a speed/time graph. The slope at every point on the speed/time graph is
the acceleration at that time.

You might be interested in

Ow do quantum numbers relate to electrons?

strojnjashka [21]

They enable us to dig deeper into the electron configurations by making us focus on electrons' quantum nature

3 0

3 years ago

A wave has a wavelength of 13 mm and a frequency of 18 hertz. What is its speed?

labwork [276]

Velocity = Frequency x Wavelength

= 18 x 13 = 234 mm/s

4 0

3 years ago

What is the streak of a mineral used for

ad-work [718]

The streak of a mineral is used for identifying what the mineral may be.

Hope this helps :)

5 0

3 years ago

Read 2 more answers

in an isolated system, two cars, each with a mass of 1,500 kg, collide. car 1 is initially at rest while car 2 is moving at 5 m/

kirza4 [7]

Answer:2.5 m/s

Explanation:

6 0

3 years ago

What average force is needed to accelerate a 7.00-gram pellet from rest to 155 m/s over a distance of 0.600 m along the barrel o

leonid [27]

Answer: The force needed is 140.22 Newtons.

Explanation:

The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.

The force exerted on the pellet is

F = m a

In order to calculate the acceleration, given the displacement d,

$d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}$

we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:

$\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}$

This value can be used to determine the time for the pellet through the barrel:

$t = \frac{d}{\overline{v}}=\frac{0.6m}{77.5\frac{m}{s}}\approx0.00774s$

Finally, we can use the above to calculate the force:

$F = ma = m\frac{2d}{t^2} = 0.007kg\cdot \frac{2\cdot 0.6 m}{0.00774^2 s^2}\approx 140.22N$

8 0

3 years ago