The correct answer is C. Colligative properties only depend upon the number of solute particles in a solution but not on the identity or nature of the solute and solvent particles. I hope this anwers your question.
Answer:
Explanation:
mole of O₂ = 
= .25 moles
mole of CO₂
= 
= .1818 moles
moles of SO₂

= .125 moles
Total moles of gas
= .5568 moles.
total volume of gas mixture
= 22.4 x .5568 liter ( volume of one mole of any gas = 22.4 liter)
= 12.47 liter.
gas will exert partial pressure according to their mole fraction
gas having greatest no of moles in the total mole will have greatest mole fraction so
O₂ will have greatest partial pressure.
Answer:

Explanation:
The volume and amount are constant, so we can use Gay-Lussac’s Law:
At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

Data:
p₁ = 1520 Torr; T₁ = 27 °C
p₂ = ?; T₂ = 150 °C
Calculations:
(a) Convert the temperatures to kelvins
T₁ = ( 27 + 273.15) K = 300.15 K
T₂ = (150 + 273.15) K = 423.15 K
(b) Calculate the new pressure

(c) Convert the pressure to atmospheres

Answer:
1.78 × 10²⁶ Atoms
Explanation:
Relation between number of molecules and moles is,
No. of Molecules = Moles × 6.022 × 10²³ Molecules/mol
No. of Molecules = 99 mol × 6.022 × 10²³ Molecules/mol
No. of Molecules = 5.96 × 10²⁵ Molecules
Also, In CO₂ Molecule there are 3 atoms.
So,
No. of atoms = 5.96 × 10²⁵ Molecules × 3
No. of atoms = 1.78 × 10²⁶ Atoms