Question

A car started to move ftom the rest and covers 2 km distance producing an acceleration of 0.5m/s2 find its velocity how long time does it take to cover the distance of 1.6km

Answer 1

(a) 44.7 m/s

We can find the final velocity of the car by using the SUVAT equation:

$v^2-u^2 = 2ad$

where

v is the final velocity

u = 0 is the initial velocity (the car starts from rest)

$a=0.5 m/s^2$ is the acceleration

$d=2km = 2000 m$ is the displacement

Solving for v,

$v=\sqrt{u^2 +2ad}=\sqrt{0+2(0.5)(2000)}=44.7 m/s$

(b) 80 s

We can find the time it takes for the car to cover 1.6 km by using the following SUVAT equation:

$d=ut+\frac{1}{2}at^2$

where in this case we have

d = 1.6 km = 1600 m is the displacement

$a=0.5 m/s^2$ is the acceleration

u = 0

t is the time

Solving for t, we find:

$t=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2(1600)}{0.5}}=80 s$