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kiruha [24]
3 years ago
7

What is the mass in grams of 3.75 × 10 21 atoms of Li?

Chemistry
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

The mass

Explanation:

the mass grams of 3.75 × 10 21 atoms of Li is

40. 21 atom of Li

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A beaker contains 175.32g of salt, NaCl(58.44g/mol). Water is added until the final volume is 2 liters. The solution should be d
cricket20 [7]

Answer:

E. 1.5M

Explanation:

because there is total 175.32 g of NaCl dissolved in 2 liter of water, and 58.44 g = 1 mol

so total miles = 175.32/58.32 = 3 moles

now 3 moles are in 2 liter of water, hence one liter contains 3/2= 1.5

Therefore answer is E. 1.5M

8 0
3 years ago
Solutions that have more h than oh- ions are
mestny [16]
They are Acids

when acids are in water they dissociate and release H+ ions into the water

while bases release OH- ions

hope that helps 
5 0
2 years ago
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Bronsted-Lowry bases are proton<br> acceptors<br> donors<br> reducers
Scrat [10]

Answer:

acceptor

Explanation:

3 0
3 years ago
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×
Anuta_ua [19.1K]

Answer:

Kc=~1.49x10^3^4}

Explanation:

We have the reactions:

A: N_2_(_g_) + O_2_(_g_)  2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9

Our <u>target reaction</u> is:

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)

We have NO_(_g_) as a reactive in the target reaction and  NO_(_g_) is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

Then if we add reactions A and B we can obtain the target reaction, so:

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9

For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}

Kc=~1.49x10^+^3^4}

3 0
3 years ago
Which of the following pairs of reactants will react together to produce water (H2O) as one of the products?
Rainbow [258]
1) <span>NaNO3 and H2O - no reaction , it is dissolution
2) no hydrogen to make water
3) </span><span>Fe(OH)3 (base) and H2SO4(acid)) 
base +acid ----> salt +water
4) </span><span>Li2O and Ba(OH)2
basic oxide and base ----> no reaction

so Answer number 3)
</span> 2Fe(OH)3 +3 H2SO4 ------>   Fe2(SO4)3 + 6H2O<span>

</span>
7 0
3 years ago
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