more energy can be produced from a fat molecule than a glucose molecule because fat molecules contain more

Chemistry

1 answer:

Pachacha [2.7K]2 years ago

4 0

Fat molecules are made up of one molecule that is glycerol and the other three are fatty acids. Lol fat

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A piece of metal with a mass of 159 g is placed in a 50 mL graduated cylinder. The water level rises from 20. mL to 41 mL. What

almond37 [142]

Volume of water displaced is equal to the volume of the metal. So 41 - 20 = 21 ml. Density = mass / volume so density = 159 / 21 = 7.57 g/ml

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3 years ago

A substance with a density of 2.70 g/mL occupies a volume of 21.3 mL. What is the mass of the sample? Report your answer in unit

katen-ka-za [31]

We know the formula of the density:
ρ = $\frac{m}{V}$ ;
So the mass will be equal to:
m = ρ * V = 2.70 * 21.3 = 57,51 g = 57510 mg of substance.
So the answer is 57510.

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3 years ago

What protects the Earth from meteorites and the sun's rays? (4 points)

inna [77]

I believe the answer is D. The atmosphere, different layers of the atmosphere can help in different ways! The stratosphere helps protect us from the sun's rays; The Mesophere is what helps protect us from meteorites! It's so cold that they burn up in that area.

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2 years ago

The atomic mass of hydrogen-1 is 1.008 and the atomic mass of helium-4 is 4.003. Find the difference in grams between 4 moles of

CaHeK987 [17]

4 moles of hydrogen = 4 * 1.008 = 4.032 grams

1 mole of helium = 4.003 grams

Difference is 4.032 - 4.003

= 0.029 g

7 0

3 years ago

Read 2 more answers

A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150

Usimov [2.4K]

Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

$M=\frac{Moles of substance X}{Volume of the solution}$

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

$11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}$

Then you can solve for the volume of the solution:

$Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL$

Hope it helps!

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3 years ago