Question

For the reaction 2A + 4B ----> 2C + 2D, at a particular instant in time, the rate of the reaction is 0.0352 M/s. What is the rate of change of B? Show Work!
A. 0.0088 M/s
B. -0.0088 M/s
C. -0.141 M/s
D. -0.0352 M/s
E. 0.141 M/s
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Answer 1

Explanation:

The given chemical equation is:

$2A + 4B -> 2C + 2D$

The rate of the reaction is 0.0352 M/s.

During the course of the reaction, the rate of reactants decreases, and the rate of products increases.

The rate of disappearance of B is shown below:

$rate=-\frac{1}{4} \frac{d[B]}{dt}$

So, rate of change of B is :

$rate of change of B =- rate * 4\\=-0.0352 M/s * 4\\=-0.1408M/s\\\\=-0.141M/s$

Option C.