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tangare [24]
3 years ago
11

What impact would adding twice as much Na2 CO3 than required for stoichiometric quantities have on the quantity of product produ

ced
Chemistry
1 answer:
IrinaK [193]3 years ago
5 0

Answer:

There will be no observed impact of adding twice as much Na2CO3 on the product

Explanation:

Stoichiometry gives the relationship between reactants and products in terms of mass, mole and volume.

If we consider the stoichiometry of the reaction, we will discover that the reaction occurs in a 1:1 ratio. This implies that use of twice the amount of Na2CO3 will only lead to an excess of Na2CO3 making the other reactant the limiting reactant. Once the other reactant is used up, the reaction quenches.

Hence, use of twice as much Na2CO3 has no impact on the quantity of product produced.

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Hey there!

It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.

In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:

m_{calcite}=15.4448g-12.4631g=2.9817g

Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:

V_{calcite}=V_{water}=\frac{13.5441g-12.4631g}{0.997g/mL}=1.084mL

Thus, the density of the calcite sample will be:

\rho _{calcite}=\frac{m_{calcite}}{V_{calcite}}\\\\\rho _{calcite}=\frac{2.9817g}{1.084mL}=2.750g/mL

This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL

Learn more:

  • brainly.com/question/12001845
  • brainly.com/question/11242138

Regards!

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2 years ago
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