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tangare [24]
3 years ago
11

What impact would adding twice as much Na2 CO3 than required for stoichiometric quantities have on the quantity of product produ

ced
Chemistry
1 answer:
IrinaK [193]3 years ago
5 0

Answer:

There will be no observed impact of adding twice as much Na2CO3 on the product

Explanation:

Stoichiometry gives the relationship between reactants and products in terms of mass, mole and volume.

If we consider the stoichiometry of the reaction, we will discover that the reaction occurs in a 1:1 ratio. This implies that use of twice the amount of Na2CO3 will only lead to an excess of Na2CO3 making the other reactant the limiting reactant. Once the other reactant is used up, the reaction quenches.

Hence, use of twice as much Na2CO3 has no impact on the quantity of product produced.

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77julia77 [94]

Answer:

yes your answer is correct

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3 years ago
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When describing metallic bonding, scientists note that the metal ions seem to be floating in a sea of electrons. This arrangemen
horrorfan [7]

True

Explanation:

Metallic bonds joins atoms of metals and alloys together. The formation of this bond type is favored by large atomic radius, low ionization energy and a large number of electrons in the valence shell.

  • This bond type is actually an attraction between the positive nuclei of all closely packed atoms in the lattice and the electron cloud jointly formed by all atoms.
  • Some of the physical properties of metals such as malleability, ductility, electrical and thermal conductivity, luster, high melting point e.t.c stems from this.

Learn more:

Bond types brainly.com/question/6071838

#learnwithBrainly

3 0
3 years ago
Average atomic mass work
babymother [125]
Take 234/100 x 0.01
then 235/100 x 0.71
then 238/100 x 99.28
you divide by 100 because the abundance is given in percentage over 100
then add up all the values, you should get an answer of 237.97 rounded up is 238.
Final answer : 238
hope this helped :)

7 0
3 years ago
A plastic bin is found to hold 3.1x10^24 molecules of water.
motikmotik

Answer:

\boxed {\boxed {\sf 5.1 \ mol \ H_2O}}

Explanation:

To convert from representative particles to moles, Avogadro's Number: 6.02*10²³, which tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance.

We can use it in a ratio.

\frac {6.02*10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}

Multiply by the given number of molecules.

3.1*10^{24} \ molecules \ H_2O*\frac {6.02*10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}

Flip the ratio so the molecules of water cancel out.

3.1*10^{24} \ molecules \ H_2O*\frac {1 \ mol \ H_2O}{6.02*10^{23} \ molecules \ H_2O}

3.1*10^{24} *\frac {1 \ mol \ H_2O}{6.02*10^{23} }

\frac {3.1*10^{24} \ mol \ H_2O}{6.02*10^{23} }

Divide.

5.14950166113 \ mol \ H_2O

The original number of molecules has 2 significant figures: 3 and 1, so our answer must have the same. For the number we calculated, that is the tenth place. The 4 in the hundredth place tells us to leave the 1.

5.1 \ mol \ H_2O

There are about 5.1 moles of water in 3.1*10²⁴ molecules of water.

5 0
2 years ago
Help pls pls pls I really need this answer
blagie [28]

Answer:

I never did this but i think its d 37.5٪ lmk if i got it right pls and srry if i didnt

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