Answer:
2.35 kgm^2
Explanation:
we take length 68.7 cm as x-axis and 47.5 cm as y-axis then the axis about which we have to find out moment of inertia will be z-axis.
moment of inertia about x-axis
kg-m2

by perpendicular axis theorem

It’s B i literally jus learned this
Answer:
I = 2 kgm^2
Explanation:
In order to calculate the moment of inertia of the door, about the hinges, you use the following formula:
(1)
I: moment of inertia of the door
α: angular acceleration of the door = 2.00 rad/s^2
τ: torque exerted on the door
You can calculate the torque by using the information about the Force exerted on the door, and the distance to the hinges. You use the following formula:
(2)
F: force = 5.00 N
d: distance to the hinges = 0.800 m
You replace the equation (2) into the equation (1), and you solve for α:

Finally, you replace the values of all parameters in the previous equation for I:

The moment of inertia of the door around the hinges is 2 kgm^2
Answer:
s = 0.9689 m
Explanation:
given,
Height of fall of paratroopers = 362 m
speed of impact = 52 m/s
mass of paratrooper = 86 Kg
From from snow on him = 1.2 ✕ 10⁵ N
now using formula
F = m a
a = F/m


Using equation of motion
v² = u² + 2 a s


s = 0.9689 m
The minimum depth of snow that would have stooped him is s = 0.9689 m
Answer:
c 275 m
Explanation:
Given parameters:
Final velocity = 73.5m/s
Unknown:
Height of fall = ?
Solution:
Since the body is falling from rest, U = 0 or initial velocity is 0m/s. Then we use one of the kinematics equation to solve this problem.
V² = U² + 2gH
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
H is the height
73.5² = 0² + (2 x 9.8 x h)
5402.25 = 19.6h
h = 275.6m