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inna [77]
3 years ago
6

How does polishing reduce friction in jewelries​

Physics
1 answer:
AlekseyPX3 years ago
7 0

Answer:

By polishing the surface, as polishing makes the surface smooth and friction can be reduced

Explanation:

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What is the speaker’s power output if the sound intensity level is 102 dBdB at a distance of 25 mm ? Express your answer to two
lesya [120]

Answer:

Power  = 124.50 W

Explanation:

Given that:

The Sound intensity of a speaker output is 102 dB

and the distance r = 25 m

For the intensity of sound,

\beta (dB)= 10 \  log_{10 } (\dfrac{I}{I_o})

where;

the threshold of hearing   I_o = 10^{-12} (W/m^2)

\dfrac{102 }{10}= log_{10}( \dfrac{I}{10^{-12}})

10^{10.2} =  \dfrac{I}{10^{-12}}

I = 10^{10.2} \times 10^{-12}

I = 0.01585 W/m²

If we recall, we know remember that ;

Power = Intensity × A rea

Power = 0.01585 W/m² × 4 × 3.142 × (25 m)²

Power  = 124.50 W

7 0
3 years ago
A 100 N force is applied to move an object a horizontal distance of 5 meters at constant speed in 10 seconds. How much power is
Tpy6a [65]

Answer:

50 W

Explanation:

<h3><u>Given :</u></h3>

  • Force applied = 100 N
  • Distance covered = 5 metres
  • Time = 10 seconds

<h3><u>To find :</u></h3>

Power

<h3><u>Solution :</u></h3>

For calculating power, we first need to know about the work done.

\bf \boxed{Work = Force \times displacement}

Now, substituting values in the above formula;

Work = 100 × 5

= 500 Nm or 500 J

We know that,

\bf \boxed{Power=\dfrac{Work\:done}{Time\: taken}}

Substituting values in above formula;

Power = 500/ 10

= 50 Nm/s or 50 W

Hence, power = 50 W .

5 0
3 years ago
Question 1<br> 2.5 cm=<br> mm
Nookie1986 [14]
There’s 10mm in a cm: 22mm
8 0
3 years ago
Read 2 more answers
In your textbook reading Chapter 26, the author suggests that an electric vehicle (EV) fleet can be used as a kind of distribute
d1i1m1o1n [39]

Answer:

Answer for the question is given in the attachment.

Explanation:

Download pdf
8 0
3 years ago
3. Calculate the wavelength of wave that has a frequency of 4.75 x 1012Hz.
Klio2033 [76]
  • Frequency=v=4.75×10^12Hz
  • Wavelength=?

We know

\boxed{\sf \lambda=\dfrac{C}{V}}

\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{4.75\times 10^{12}s^{-1}}

\\ \sf\longmapsto \lambda=0.631\times 10^{-4}m

\\ \sf\longmapsto \lambda=6.31\times 10^{-5}m

4 0
3 years ago
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