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3 years ago

What happens to the standing wave frequencies if you quadruple the tension in the string?

Physics

1 answer:

kramer3 years ago

8 0

Answer:

. A standing wave on a string (fixed at both ends) has a fundamental frequency f. If you quadruple the tension in the string, how can you change the length of the string so that the fundamental frequency remains the same? ... double the length.

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Simple pendulum, is show in several states In case A the mass is travelling back down to the bottom and is in between the bottom

uysha [10]

The angular acceleration is maximum in case C

Explanation:

The motion of the bob in the simple pendulum is a portion of a circular motion. In a circular motion, the angular acceleration is related to the tangential acceleration by

$a=\alpha r$

where

a is the tangential acceleration

$\alpha$ is the angular acceleration

r is the radius (the length of the pendulum)

Moreover for a pendulum, the tangential acceleration is given by the component of the acceleration of gravity in the tangential direction, so

$a=g sin \theta$

where

g is the acceleration of gravity

$\theta$ is the angle of the pendulum with the vertical

So we have

$\alpha = \frac{g sin \theta}{r}$

Since g and r are constant, we see that the angular acceleration is proportional to the angle: the larger the angle, the larger the angular acceleration, and the smaller the angle, the smaller the angular acceleration.

Therefore, the angular acceleration is maximum when the pendulum is at its maximum height, and zero when it is at the lowest position. So, the correct statements are

It is maximum in case C

Learn more about periodic motion:

brainly.com/question/5438962

#LearnwithBrainly

3 0

3 years ago

Acceleration will only speed up an object true or false

EleoNora [17]

Yes
Acceleration, in physics, is the rate of change of velocity of an object.

6 0

3 years ago

an 80 kg cart goes around the inside of a vertical loop of a roller coaster. the radius of the loop is 5m and the cart moves at

GarryVolchara [31]

Answer:

F= 224 N

Explanation:

Given that

mass ,m = 80 kg

Radius ,r= 5 m

speed at the top v= 8 m/s

The force at the top = F

Now by using the Second law of Newton's

$F+mg=\dfrac{mv^2}{r}$

Now by putting the values

$F+80\times 10 = \dfrac{80\times 8^}{5}$

Take g = 10 m/s²

$F= \dfrac{80\times 8^2}{5}-800$

F= 224 N

Therefore the force exerted by the track at the top position will be 224 N.

3 0

4 years ago

How will the motion of an object that is moving to the right change, if it is pushed in the opposite direction with a greater fo

Liono4ka [1.6K]

ويويوسوسوسميىيىطنطنظنسنسنمسم ستسري ستي تس ستي تس ستي تس ستي سر س

4 0

3 years ago

How many more neutrons are in a I SOTOPE of copper-14 than in standard carbon atom

sweet-ann [11.9K]

Answer:

2 more neutrons

Explanation:

To obtain the answer to the question, let us calculate the number of neutrons in carbon–14 and standard carbon (i.e carbon–12). This can be obtained as follow:

For carbon–14:

Mass number = 14

Proton number = 6

Neutron number =?

Mass number = Proton + Neutron

14 = 6 + Neutron

Collect like terms

14 – 6 = Neutron

8 = Neutron

Neutron number = 8

For carbon–12:

Mass number = 12

Proton number = 6

Neutron number =?

Mass number = Proton + Neutron

12 = 6 + Neutron

Collect like terms

12 – 6 = Neutron

6 = Neutron

Neutron number = 6

SUMMARY:

Neutron number of carbon–14 = 8

Neutron number of carbon–12 = 6

Finally, we shall determine the difference in the neutron number. This can be obtained as follow:

Neutron number of carbon–14 = 8

Neutron number of carbon–12 = 6

Difference =?

Difference = (Neutron number of carbon–14) – (Neutron number of carbon–12)

Difference = 8 – 6

Difference = 2

Therefore, carbon–14 has 2 more neutrons than standard carbon (i.e carbon–12)

3 0

3 years ago