Answer: 5.72 x 10-3Ω
Explanation:
Hi, to answer this question, first we have to calculate the cross sectional area of the cable:
Diameter (D)=6.07 mm
Since: 1000mm = 1m
6.07mm/ 1000mm/m = 0.00607 meters
Area of a circle : π (d/2)^2
A = π (0.00607/2)^2= 0.000028937 m2
Resistance formula:
Resistance (R) = P(resistivity) L (length)÷A (cross sectional area )
Replacing with the values given:
R = (2.82x10-8 x 5.87) / 0.000028937
R = 5.72 x 10-3Ω
Feel free to ask for more if needed or if you did not understand something.
Answer:
The work flow required by the compressor = 100.67Kj/kg
Explanation:
The solution to this question is obtained from the energy balance where the initial and final specific internal energies and enthalpies are taken from A-17 table from the given temperatures using interpolation .
The work flow can be determined using the equation:
M1h1 + W = Mh2
U1 + P1alph1 + ◇U + Workflow = U2 + P2alpha2
Workflow = P2alpha2 - P1alpha1
Workflow = (h2 -U2) - (h1 - U1)
Workflow = ( 684.344 - 491.153) - ( 322.483 - 229.964)
Workflow = ( 193.191 - 92.519)Kj/kg
Workflow = 100.672Kj/kg
Answer:
because each row increases in atomic mass by a specific number, so anything over five is in the second row.
