A mixture containing 21.4 g of ice (at exactly 0.00 ∘C) and 75.3 g of water (at 80.2 ∘C) is placed in an insulated container.
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The H⁺ ion concentration can be calculated from pH values using the following equation:
1.) Given pH = 2
Using the above equation, 2 = - log [H⁺]
Therefore, [H⁺] = 10⁻² mol/L
2.) Given pH = 6
Using the same equation, we have 6 = - log [H⁺]
Hence, [H⁺] = 10⁻⁶ mol/L
3.) Taking the ratio of [H⁺] for pH = 2 and pH = 6, we have
= 10⁴
So, there are 10,000 times more H⁺ ions in a solution of pH = 2 than that of pH = 6.