Answer:
a) The car was moving at a speed of ![29.167\ m.s^{-1}](https://tex.z-dn.net/?f=29.167%5C%20m.s%5E%7B-1%7D)
b) The negative sign of
denotes that the observer is coming towards the police car which is the source of the sound.
c) ![f_o=1283.33\ Hz](https://tex.z-dn.net/?f=f_o%3D1283.33%5C%20Hz)
Explanation:
Given:
- original frequency of the source,
![f=1200\ Hz](https://tex.z-dn.net/?f=f%3D1200%5C%20Hz)
- speed of the source,
![v_s=0\ m.s^{-1}](https://tex.z-dn.net/?f=v_s%3D0%5C%20m.s%5E%7B-1%7D)
- velocity of the obstacle car be,
![v_o](https://tex.z-dn.net/?f=v_o)
- speed of sound,
![s=350\ m.s^{-1}](https://tex.z-dn.net/?f=s%3D350%5C%20m.s%5E%7B-1%7D)
- observed frequency,
![f_o=1100\ Hz](https://tex.z-dn.net/?f=f_o%3D1100%5C%20Hz)
<u>Using the equation from the Doppler's effect:</u>
![\frac{f_o}{f} =\frac{(s+v_o)}{(s-v_s)}](https://tex.z-dn.net/?f=%5Cfrac%7Bf_o%7D%7Bf%7D%20%3D%5Cfrac%7B%28s%2Bv_o%29%7D%7B%28s-v_s%29%7D)
![\frac{1100}{1200} =\frac{(350+v_o)}{350-0}](https://tex.z-dn.net/?f=%5Cfrac%7B1100%7D%7B1200%7D%20%3D%5Cfrac%7B%28350%2Bv_o%29%7D%7B350-0%7D)
![v_o=-29.167\ m.s^{-1}](https://tex.z-dn.net/?f=v_o%3D-29.167%5C%20m.s%5E%7B-1%7D)
a)
The car was moving at a speed of ![29.167\ m.s^{-1}](https://tex.z-dn.net/?f=29.167%5C%20m.s%5E%7B-1%7D)
b)
The negative sign of
denotes that the observer is coming towards the police car which is the source of the sound.
c)
Now when, ![v_s=50\ m.s^{-1}](https://tex.z-dn.net/?f=v_s%3D50%5C%20m.s%5E%7B-1%7D)
Then, ![f_o=?](https://tex.z-dn.net/?f=f_o%3D%3F)
Using the Doppler's eq.:
![\frac{f_o}{1200} =\frac{(350+(-29.167))}{(350-50)}](https://tex.z-dn.net/?f=%5Cfrac%7Bf_o%7D%7B1200%7D%20%3D%5Cfrac%7B%28350%2B%28-29.167%29%29%7D%7B%28350-50%29%7D)
![f_o=1283.33\ Hz](https://tex.z-dn.net/?f=f_o%3D1283.33%5C%20Hz)
Answer:
vp = 0.94 m/s
Explanation
Formula
Vp = position/ time
position: Initial position - Final position
Position = 25 m - (-7 m) = 25 m + 7 m = 32 m
Then
Vp = 32 m / 34 seconds
Vp = 0.94 m/s
Answer:
t = 2.13 10-10 s
, d = 6.39 cm
Explanation:
For this exercise we use the definition of refractive index
n = c / v
Where n is the refraction index, c the speed of light and v the speed in the material medium.
The refractive indices of ice and crown glass are 1.13 and 1.52, respectively, therefore the speed of the beam in the material medium is
v = c / n
As the beam strikes perpendicularly, the beam path is equal to the distance of the leaves, there is no refraction, so we can use the uniform motion relationships
v = d / t
t = d / v
t = d n / c
Let's look for the times on each sheet
Ice
t₁ = 1.4 10⁻² 1.31 / 3 10⁸
t₁ = 0.6113 10⁻¹⁰ s
Crown glass (BK7)
t₂ = 3.0 10⁻² 1.52 / 3.0 10⁸
t₂ = 1.52 10⁻¹⁰ s
Time is a scalar therefore it is additive
t = t₁ + t₂
t = (0.6113 + 1.52) 10⁻¹⁰
t = 2.13 10-10 s
The distance traveled by this time in a vacuum would be
d = c t
d = 3 10⁸ 2.13 10⁻¹⁰
d = 6.39 10⁻² m
d = 6.39 cm
Well, electrons can be converted into a atomic number so if SE atomic number is 34 that means it has 34 electrons. AI has a atomic number of 13 meaning it has 13 electrons.
So the difference is that SE has more electrons then AI.
Hope this helped. :D