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Slav-nsk [51]
3 years ago
9

Which temperatures originally represented the fixed points Celsius temperature scale?

Chemistry
1 answer:
frez [133]3 years ago
8 0

Answer:Since 1743 the Celsius scale has been based on 0 °C for the freezing point of water and 100 °C for the boiling point of water at 1 atm pressure. Prior to 1743 the values were reversed (i.e. the boiling point was 0 degrees and the freezing point was 100 degrees).

Explanation: i no it

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A sample of gas initially occupies 4.25 L at a pressure of 0.850 atm at 23.0°C. What will the volume be if the temperature is ch
Akimi4 [234]

Answer:

2.31\text{ L}

Explanation:

Here, we want to calculate the final volume

We use the general gas equation here:

\frac{P_1V_1}{T_1}\text{ = }\frac{P_2V_2}{T_2}

P1 is the initial pressure which is 0.850 atm

V1 is the initial volume which is 4.25 L

T1 is the initial temperature which is (23 + 273.15 = 296.15 K)

P2 is the final pressure which is 1.50 atm

V2 is the final volume which is unknown

T2 is the final temperature (11.5 + 273.15 = 284.65 K)

Substituting the values, we have:

\begin{gathered} \frac{0.850\text{ }\times4.25}{296.15}\text{ = }\frac{1.50\times V_2}{284.65} \\  \\ V_2\text{ = }\frac{284.65\text{ }\times0.850\times4.25}{1.5\times296.15} \\  \\ V_2\text{ = 2.31 L} \end{gathered}

6 0
1 year ago
how would physical changes to Earth such as an iceberg or rising sea levels lead to physical changes in organisms?
vlabodo [156]
If there was more water area and less land more animals would adapt to the water life than land. Like for example more evolving fins or even amphibians
just staying in water and no longer needing legs or the things they use for living on the land. 

7 0
3 years ago
I need to know all the answers for this homework!!!!
maw [93]

1. 100 C

2. Point B to C is the ices heat capacity

3. During the points D to E the bonds of the water molecules build up enough kinetic energy to break their intermolecular bonds (not intra), which can lead to gas.

4. Between points D and E the energy is being released the energy required is equivalent along the line.

5. Between point E and D the water is converting to water (condensation)

6. Energy is being released 2260 j/g

7. Yes, but only under extreme volumetric pressures

8. D and E or B and C

9. Freezing (the water is also becoming less dense)

10. Melting or if water already, absorbtion of energy

11. released.

5 0
3 years ago
The water-gas shift reaction CO(g)+H2O(g)⇌CO2(g)+H2(g) is used industrially to produce hydrogen. The reaction enthalpy is ΔH∘=−4
denis23 [38]

Answer:

To increase the yield of H₂ we would use a low temperature.

For an exothermic reaction such as this, decreasing temperature increases the value of K and the amount of products at equilibrium. Low temperature increases the value of K and the amount of products at equilibrium.

Explanation:

Let´s consider the following reaction:

CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g)

When a system at equilibrium is disturbed, the response of the system is explained by Le Chatelier's Principle: <em>If a system at equilibrium suffers a perturbation (in temperature, pressure, concentration), the system will shift its equilibrium position to counteract such perturbation</em>.

In this case, we have an exothermic reaction (ΔH° < 0). We can imagine heat as one of the products. If we decrease the temperature, the system will try to raise it favoring the forward reaction to release heat and, at the same time, increasing the yield of H₂. By having more products, the value of the equilibrium constant K increases.

3 0
3 years ago
Calculate the volume of dry co2 produced at body temperature (37 ∘c) and 0.970 atm when 25.5 g of glucose is consumed in this re
katrin2010 [14]

I believe the balanced chemical equation is:

C6H12O6 (aq) + 6O2(g) ------> 6CO2(g) + 6H2O(l) 

 

First calculate the moles of CO2 produced:

moles CO2 = 25.5 g C6H12O6 * (1 mol C6H12O6 / 180.15 g) * (6 mol CO2 / 1 mol C6H12O6)

moles CO2 = 0.8493 mol

 

Using PV = nRT from the ideal gas law:

<span>V = nRT  / P</span>

V = 0.8493 mol * 0.08205746 L atm / mol K * (37 + 273.15 K) / 0.970 atm

<span>V = 22.28 L</span>

6 0
3 years ago
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