Answer:
0.01 faraday
Explanation:
We'll begin by writing the balanced equation. This is illustrated below:
CaCl₂ (aq) —> Ca²⁺ (aq) + 2Cl¯ (aq)
Ca²⁺ (aq) + 2e —> Ca
Molar mass of Ca = 40 g/mol
Mass of Ca from the balanced equation = 1 × 40 = 40 g
1 mole of electron (e) = 1 faraday
2 moles of electrons (e) = 2 × 1 faraday
2 moles of electrons (e) = 2 faraday
From the balanced equation above,
40 g of Ca was deposited by 2 faraday.
Therefore, 0.2 g of Ca will be deposited by = (0.2 × 2)/40 = 0.01 faraday.
Thus, 0.01 faraday is needed for the reaction.
