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Dmitry [639]
3 years ago
5

How many Faraday is needed to deposit 0.2 g of Calcium (Ca) from CaCl2 solution using electrolysis process.

Chemistry
1 answer:
EastWind [94]3 years ago
4 0

Answer:

0.01 faraday

Explanation:

We'll begin by writing the balanced equation. This is illustrated below:

CaCl₂ (aq) —> Ca²⁺ (aq) + 2Cl¯ (aq)

Ca²⁺ (aq) + 2e —> Ca

Molar mass of Ca = 40 g/mol

Mass of Ca from the balanced equation = 1 × 40 = 40 g

1 mole of electron (e) = 1 faraday

2 moles of electrons (e) = 2 × 1 faraday

2 moles of electrons (e) = 2 faraday

From the balanced equation above,

40 g of Ca was deposited by 2 faraday.

Therefore, 0.2 g of Ca will be deposited by = (0.2 × 2)/40 = 0.01 faraday.

Thus, 0.01 faraday is needed for the reaction.

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BOTH acids and bases
wlad13 [49]

Answer:

Hello There!

Explanation: Your Answer will be, D) conduct electricity in water.

Both acids and bases conducts electricity and water.

When acid dissolves in water, they are good electrolytes.

When bases dissolves in water they are good electrolytes.

Electrolytes are liquid or molten substances that are able to conduct electricity.

they conduct electricity by the use of their ions in solution.

Since acid and bases ionize in solution, they will conduct electricity.

An acid is a substance that produces excess hydroxonium ion in solution.

A base produces excess hydroxyl ions in solution. Hope This Helps!

8 0
3 years ago
Read 2 more answers
Consider the following reaction: Cd (s) AgCl (aq) --> CdCl2 (aq) Ag (s) In this reaction, a. electrons are transferred from s
madam [21]

Answer:

a. electrons are transferred from silver in AgCl (aq) to Cd (s)

Explanation:

In this reaction Ag is reduced:

  • Ag⁺ + 1e⁻ → Ag⁰

While Cd is oxidized:

  • Cd⁰ → Cd⁺² + 2e⁻

With those two semi-reactions we can see that there's a transfer of electrons from silver in AgCl(aq) to the solid cadmium.

For the record, given that Ag was reduced, Cd was the reducing agent. And because Cd was reduced, Ag was the oxidizing agent.

6 0
3 years ago
The energy of motion is called
timama [110]

Answer:I think it’s mechanical energy

Explanation:

3 0
3 years ago
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4. Can 200 ml of fluid be transferred to a 1-quart container? Explain the process that you used to arrive at your answer.
sukhopar [10]

Answer:

  • <u><em>Yes, 200 ml of fluid can be transferred to a 1-quart container.</em></u>

Explanation:

You must compare the two volumes, 200 ml and 1 quart. If 200 ml is less than or equal to 1 quart, then 200 ml of fluid can be transferred to a 1-quart container, else it is not possible.

To compare, the two volumes must be on the same system of units.

Quarts is a measure of volume equivalent to 1/4 of gallon.

One gallon is approximately 3.785 liters.

3.785 liter = 3.785 liter × 1,000 ml/liter

Then, to convert 1 quart to ml use the unit cancellation method:

  • (1/4)gallon × 3.785 liter/gallon × 1,000ml / liter = 946.25 ml

Thus, you get that a 1-quart container has volume of 946.25 ml, which allows that 200ml of fluid be transferred to it.

7 0
4 years ago
What is the volume of 45.0 grams of nitrogen monoxide , NO
gladu [14]

Answer:

V=37.05\ L

Explanation:

Given that:

Mass of NO, m = 45.0 g

Molar mass of NO, M = 30.01 g/mol

Temperature = 20.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (20.0 + 273.15) K = 293.15 K

V = ?

Pressure = 740 mm Hg

Considering,  

n=\frac{m}{M}

Using ideal gas equation as:

PV=\frac{m}{M}RT

where,  

P is the pressure

V is the volume

m is the mass of the gas

M is the molar mass of the gas

T is the temperature  

R is Gas constant having value = 62.36367 L. mmHg/K. mol

Applying the values in the above equation as:-

740\times V=\frac{45.0}{30.01}\times 62.36367\times 293.15

740V=\frac{822685.94372}{30.01}

V=37.05\ L

3 0
3 years ago
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