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bekas [8.4K]
3 years ago
6

PLEASE HELP ME !!!!!!!!

Physics
1 answer:
Tresset [83]3 years ago
4 0

☝️☝️☝️

jeheiebhejenelneiebeyueveusnzisk

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A uniform rod of length L is pivoted at L/4 from one end. It is pulled to one side through a very small angle and allowed to osc
ludmilkaskok [199]

Answer:

T= 4.24sec

Explanation:

We are going to use the formula below to calculate.

T=2\pi \sqrt{\frac{L}{g} }

Where T is period

           L is length of rod

       g is acceleration due to gravity =     9.8m/s^{2}

From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this L_{O}

L_{O} = 3/4 * 5.95m

        = 4.4625m

thus   T=2\pi \sqrt{\frac{L_{O} }{g} }

          T=2\pi \sqrt{\frac{4.4625 }{9.8} }

          T= 4.24sec

8 0
4 years ago
What is the nature of the distance time graph for motion of an object.
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4 years ago
How much force is required to accelerate a 22Kg mass at 6 m/s?
GuDViN [60]

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F = 132N

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4 years ago
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You are tasked with completing the Venn diagram comparing weather
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8 0
3 years ago
A pickup truck is carrying a toolbox, but the rear gate of the truck is missing, so the box will slide out if it is set moving.
Anon25 [30]

Answer:

t=7.33 s

Explanation:

According to Newton's second law:

\sum F=m*a

because we don't want the box to slide, the acceleration has to be zero.

\sum F=-F_{friction}+F_{truck}=0\\F_{truck}=F_{friction}\\F_{friction}=\µ*m*g=0.500*9.81*m\\F_{friction}=4.91*m

we know that:

F=m*a\\4.91m=m*a\\a=4.91m/s^2

Now having the acceleration, we can use the following formula.

v_f=a*t\\t=\frac{36.0m/s}{4.91m/s^2}\\\\t=7.33s

7 0
3 years ago
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