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Alex787 [66]
3 years ago
14

Which action will leave the dump trucks inertia unchanged?? PLEASE ANSWER FAST!!!

Physics
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

B.

Explanation:

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Which of the following is a source of thermal energy that is absorbed by Earth's atmosphere?
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Answer:

100% of the energy entering earth's atmosphere comes from the sun. ~50% of the incoming energy is absorbed by the earth's surface i.e. the land and oceans.

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A car is driving due South<br> counterclockwise on a<br> circular track.
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Answer:

a

Explanation:hope this helps

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A total Δν of 15 km/s is required to achieve an interplanetary mission. The proposed rocket has two stages. The first stage alon
AlexFokin [52]

Answer:

102000 kg

Explanation:

Given:

A total Δν = 15 km/s

first stage mass = 1000 tonnes

specific impulse of liquid rocket =  300 s

Mass flow rate of liquid fuel = 1500 kg/s

specific impulse of solid fuel = 250 s

Mass flow of solid fuel = 200 kg/s

First stage burn time = 1 minute = 1 × 60 seconds = 60 seconds

Now,

Mass flow of liquid fuel in 1 minute = Mass flow rate × Burn time

or

Mass flow of liquid fuel in 1 minute = 1500 × 60 = 90000 kg

Also,

Mass flow of solid fuel in 1 minute = Mass flow rate × Burn time

or

Mass flow of solid fuel in 1 minute = 200 × 60 = 12000 kg

Therefore,

The total jettisoned mass flow of the fuel in first stage

= 90000 kg +  12000 kg

= 102000 kg

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3 years ago
((Bruv pls hurry on test)) Radioisotopes often emit alpha particles, beta particles, or gamma rays. The distance they travel thr
Jlenok [28]

Answer:

A,B,,G

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3 0
3 years ago
Read 2 more answers
A planet has two small satellites in circular orbits around the planet. The first satellite has a period 18.0 hours and an orbit
sasho [114]

Answer:

Time period of second satellite will be 50.904 hour

Explanation:

We have given time period of first satellite T_1=18hour

Orbital radius of first satellite a_1=2\times 10^7m

Orbital radius of second satellite a_2=4\times 10^7m

We have to find the time period of second satellite.

Time period of satellite is equal to T=2\pi \sqrt{\frac{a^3}{G(M_1+M_2)}}

From the relation we can see that T\propto a^{\frac{3}{2}}

\frac{T_1}{T_2}=\frac{a_1^\frac{3}{2}}{a_2^\frac{3}{2}}

\frac{18}{T_2}=\frac{(2\times 10^7)^\frac{3}{2}}{(4\times 10^7)^\frac{3}{2}}

\frac{18}{T_2}=(\frac{1}{2})^\frac{3}{2}

T_2=50.904hour

Time period of second satellite will be 50.904 hour

4 0
3 years ago
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