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valentina_108 [34]
3 years ago
15

Which of the following can easily reverse motion and are better at varying speeds than electrical motors?

Engineering
2 answers:
yan [13]3 years ago
6 0

Answer:

fluid power system

Explanation:

satela [25.4K]3 years ago
4 0
Fluid power system

Example
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Water vapor at 1.0 MPa, 300°C enters a turbine operating at steady state and expands to 15 kPa. The work developed by the turbin
Andre45 [30]

Answer:

a) isentropic efficiency = 84.905%

b) rate of entropy generation = .341 kj/(kg.k)

Please kindly see explaination and attachment.

Explanation:

a) isentropic efficiency = 84.905%

b) rate of entropy generation = .341 kj/(kg.k)

The Isentropic efficiency of a turbine is a comparison of the actual power output with the Isentropic case.

Entropy can be defined as the thermodynamic quantity representing the unavailability of a system's thermal energy for conversion into mechanical work, often interpreted as the degree of disorder or randomness in the system.

Please refer to attachment for step by step solution of the question.

5 0
3 years ago
The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is 5.5 x 106 Btu/h. The comb
Veronika [31]

Answer:

Explanation:uhhhhhh all?

7 0
3 years ago
The modulus of elasticity for a ceramic material having 6.0 vol% porosity is 303 GPa. (a) Calculate the modulus of elasticity (i
Phantasy [73]

Answer:

modulus of elasticity for the nonporous material is 340.74 GPa

Explanation:

given data

porosity = 303 GPa

modulus of elasticity = 6.0

solution

we get here  modulus of elasticity for the nonporous material Eo that is

E = Eo (1 - 1.9P + 0.9P²)    ...............1

put here value and we get Eo

303 = Eo ( 1 - 1.9(0.06) + 0.9(0.06)² )  

solve it we get

Eo = 340.74 GPa

8 0
3 years ago
What are the three main sections of a nuclear power plant?
strojnjashka [21]
The reactor, generator, and the cooling towers
7 0
2 years ago
Water flows with an average speed of 6.5 ft/s in a rectangular channel having a width of 5 ft The depth of the water is 2 ft.
lisov135 [29]

Answer:

specific energy  = 2.65 ft

y2 = 1.48 ft  

Explanation:

given data

average speed v = 6.5 ft/s

width = 5 ft

depth of the water y = 2 ft

solution

we get here specific energy that is express as

specific energy = y + \frac{v^2}{2g}     ...............1

put here value and we get

specific energy = 2 + \frac{6.5^2}{2\times 9.8\times 3.281}  

specific energy  = 2.65 ft

and

alternate depth is

y2 = \frac{y1}{2} \times (-1+\sqrt{1+8Fr^2})  

and

here Fr² = \frac{v1}{\sqrt{gy}}  = \frac{6.5}{\sqrt{32.8\times 2}}  

Fr² = 0.8025

put here value and we get

y2 = \frac{2}{2} \times (-1+\sqrt{1+8\times 0.8025^2})

y2 = 1.48 ft  

7 0
3 years ago
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