Question

The outer surface of a spacecraft in space has an emissivity of 0.44 and a solar absorptivity of 0.3. If solar radiation is incident on the spacecraft at a rate of 950 W/m2, determine the surface temperature of the spacecraft when the radiation emitted equals the solar energy absorbed.

Answer 1

Answer:

$T=326.928K$

Explanation:

From the question we are told that:

Emissivity $e=0.44$

Absorptivity $\alpha =0.3$

Rate of solar Radiation $R=0.3$

Generally the equation for Surface absorbed energy is mathematically given by

 $E=\alpha R$

 $E=0.3*950$

 $E=285W/m^2$

Generally the equation for Emitted Radiation is mathematically given by

 $\mu=e(\sigmaT^4)$

Where

T=Temperature

 $\sigma=5.67*10^8Wm^{-2}K_{-4}$

Therefore

 $\alpha*E=e \sigma T^4$

 $0.3*(950)=0.44(5.67*10^-8)T^4$

 $T=326.928K$