The highest sequence for this shell is the number 2, preceding both the s and p in the diagram. This means that the outermost shell is the second level shell. In this shell, there are 7 electrons, 2 in the 2s orbital and 5 in the 2p orbital.
As a side note (not sure if this is a typo), the electron structure for fluorine begins with a 1s2, not a 1s1.
Answer:
Lithium oxide, Li₂O.
Explanation:
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In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:
Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:
Thus, we perform the operations in order to obtain:
So we solve for x as shown below:
Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.
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We are given with a vinegar with a hydrogen ion concentration of 0.00010 m. We are asked to express this concentration in scientific notation. The answer when expressed in scientific notation is 1x10^-4 m or molality. Answer is <span>1x10^-4 m. </span>
Answer:
Mass = 28.08
Explanation:
Given data:
Mass of Al₂O₃ = 21.8 g
Mass of water = 9.7 g
Mass of Al(OH)₃ = ?
Solution:
Chemical equation:
2Al(OH)₃ → Al₂O₃ + 3H₂O
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 9.7 g/ 18 g/mol
Number of moles = 0.54 mol
Number of moles of Al₂O₃:
Number of moles = mass/molar mass
Number of moles = 21.8 g/ 101.96 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of Al(OH)₃ with Al₂O₃ and H₂O.
Al₂O₃ : Al(OH)₃
1 : 2
0.21 : 2×0.21 = 0.42 mol
H₂O : Al(OH)₃
3 ; 2
0.54 : 2/3×0.54 = 0.36 mol
Mass of Al(OH)₃:
Mass = number of moles × molar mass
Mass = 0.36 mol × 78 g/mol
Mass = 28.08 g
