Answer:
a direct current goes in one direction at all times whereas an alternating current goes back and forth in a circuit
The correct answer is
<span> 4. protons are positively charged.
In fact, the direction of the electric field of a charged particle depends on the sign of the charge of the particle. While a negatively charged particle (such as the electron) produces an electric field that points toward the charge, a positively charged particle (like a proton) produces an electric field that points away from the charge. This can be proofed by using a positive test charge: if we put a positive test charge near a proton, this test charge will move away from the proton (because it is repelled from it, since they have same charge), and the direction of its motion gives the direction of the electric field generated by the proton, so away from it.</span>
Hello.
h=150 m
u(initial speed)=0
t=5.5 s
<span>v(final speed) =?
</span>
2gh=v^2-u^2
Have a nice day
Answer:
a)t = 0.323 sec
b)t'= 0.323 sec
c)|h|= 0.52 m
d)y=1.56 m
Explanation:
The speed of ball ,U=104 km/h
U = 104 x 5/18 m/s =28.88 m/s
x= 18.3 m
a)
The half of distance = 18.3/2=9.15 m
We know that
Distance = Velocity x time
9.15 = 28.28 .t
t = 0.323 sec
b)
The total time to cover distance 18.3 m
18.3 = 28.88 x T
T=0.646 m
So the second half distance will cover in t' time
t' = T -t
t' = 0.646 - 0.323
t' = 0.323 s
c)
Initial velocity in y direction is zero.
Vo= 0
![h=V_o.t-\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=h%3DV_o.t-%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
![h=0-\dfrac{1}{2}\ttimes 10\times 0.323^2](https://tex.z-dn.net/?f=h%3D0-%5Cdfrac%7B1%7D%7B2%7D%5Cttimes%2010%5Ctimes%200.323%5E2)
h= - 0.52 m ( this is displacement and we know that it is a vector)
So magnitude of |h|= 0.52 m
d)
![H=V_o.T-\dfrac{1}{2}gT^2](https://tex.z-dn.net/?f=H%3DV_o.T-%5Cdfrac%7B1%7D%7B2%7DgT%5E2)
H= - 2.08 m
|H|= 2.08 m
So the in second half y = H- h
y= 2.08 - 0.52 m
y=1.56 m