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Tju [1.3M]
3 years ago
5

Guys please answer me i will be really thankful

Physics
1 answer:
Alona [7]3 years ago
3 0
I believe that says that the car is going 125 meter per 5 seconds
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The electric potential at a point equidistant from two particles that have charges +Q and –Q is larger than zero. a. smaller tha
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4 years ago
The inner and outer surfaces of a cell membrane carry a negative and positive charge respectively. Because of these charges, a p
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Answer:

The magnitude of the electric field inside the membrane is 8.8×10⁶V/m

Explanation:

The electric field due to electric potential at a distance Δs is given by

E=ΔV/Δs

We have to find the magnitude electric field in the membrane

Ecell= -ΔV/Δs

E_{cell}=-\frac{V_{in}-V_{out}}{s} \\E_{cell}=\frac{V_{out}-V_{in}}{s}\\E_{cell}=\frac{0.070V}{8*10^{-9}m } \\E_{cell}=8.8*10^{6}V/m

The magnitude of the electric field inside the membrane is 8.8×10⁶V/m

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3 years ago
A couple of ice cubes float in a glass of water. Will the water level in the glass
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6 0
3 years ago
Electromagnet Fluctation
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Answer:

answer choice B

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3 years ago
When a car of mass 1200 kg, going with speed 30 m/s, rounds an unbanked curve of radius 150 m, what is the minimum coefficient o
Nana76 [90]

Answer:

\mu_s=0.61

Explanation:

In order for the car does not slip, the frictional force must be equal to the centripetal force due to the circular motion. According to the free body diagram:

\sum F_y:N=mg\\\sum F_x:F_f=F_c

The frictional force is given by:

F_f=\mu_s N=\mu_s mg

The centripetal force is defined as:

F_c=ma_c=m\frac{v^2}{r}

Here v is the linear speed and r is the radius of the circular motion. Replacing this equations:

\mu_smg=m\frac{v^2}{r}\\\mu_s=\frac{v^2}{gr}\\\mu_s=\frac{(30\frac{m}{s})^2}{(9.8\frac{m}{s^2})(150m)}\\\mu_s=0.61

8 0
4 years ago
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