<span>The shortening velocity refers to the speed of the contraction from the muscle shortening while lifting a load. Maximal shortening velocity is only attained with a minimal load. With a light load, the shortening velocity is at its Maximal shortening velocity. When the weight is heavy, the speed in which the muscle lifts the weight decreases in speed at a slower velocity.</span>
A) Geothermal
B) Hydroelectric
C)Biomass
D) Wind
I assume this is the four options you had, correct?
i think that biomass is the only one that would release the greenhouse gases. I once heard, it may not be true, that biomass has more co2 released than coal.
Answer:
a)F=3 x 10⁻⁷ N
b)x=2.405 m
Explanation:
Given that
m₁=295 kg
m₂=595 kg
d= 4.1 m
a)
m₃=63 kg
r=d/2 = 2.05 m
The force between the mass m₁ and m₃

by putting the values


F₁₃=2.94 x 10⁻⁷ N
The force between the mass m₂ and m₃
by putting the values


F₂₃=5.94 x 10⁻⁷ N
The net force F
F= F₂₃- F₁₃
F=5.94 x 10⁻⁷ N-2.94 x 10⁻⁷ N
F=3 x 10⁻⁷ N
b)
Lest take at distance x from mass m₂ net force is zero.


Form above two equation



x²=2.01(4.1-x)²
x=1.42 (4.1-x)
x=5.82 - 1.42x
x=2.405 m
Answer:
t = 39.04 1010 year
Explanation:
This is a nuclear disintegration exercise that is governed by the equation.
N = N0 e (-lam t)
The average life time is related to nuclear activity
T ½ = ln 2 / lam
Let's use these two equations for exercise, let's start by finding nuclear activity
Lam = ln 2 / T ½
Lam = ln 2 / 4.9 10 10
Lam = 0.14146 10-10 y-1
They tell us that the relationship atoms
No / N = 0.0040
Let's look
No / N = 1/0040
N/No = 250
Let's calculate the time
(-lam t) = ln (N / No)
, t = - 1 / lam ln (n / No)
t = - 1 / 0.14146 10-10 ln (250)
t = 39.04 1010 year
i think its a, good luck on your test