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Elis [28]
3 years ago
11

8. The following system contains 20.0 psi each of gases A and B in the end bulbs with an evacuated bulb in the centre. Both stop

cocks are opened at once. What is the new overall pressure in the system?
I literally have no idea how to even start this, I know that the answer is 13.3 psi, but I don't have any clue why or how to get there.

Chemistry
1 answer:
Effectus [21]3 years ago
3 0

Answer:

13.3

Explanation:

Before opening the stopcocks you have 40psi in total.

After that, those 40psi will be divided into 3bulbs, so 40/3=13.3psi for the system.

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If, at a given temperature, the equilibrium constant for the reaction H2(g) Cl2(g) 2HCl(g) is Kp, then the equilibrium constant
ankoles [38]

Answer:

Kp = [(PH2/P°)∧(1/2)eq]*[(PCl2/P°)∧(1/2)eq] / (PHCl(g)/P°)eq

Explanation:

  • H2(g) + Cl2(g) → 2HCl(g)

∴ Kp = F(T)

⇒ Kp = (PHCl/P°)eq / [(PCl2/P°)eq]*[(PH2/P°)eq]

∴ P° = 1 bar

  • HCl(g) → (1/2)H2(g) + (1/2)Cl2(g)

⇒ Kp = [(PH2/P°)∧(1/2)eq]*[(PCl2/P°)∧(1/2)eq] / (PHCl(g)/P°)eq

4 0
3 years ago
Which of the following is NOT an indication of a chemical reaction?
PolarNik [594]
A. The substance dissolved. Just because a substance dissolved in a solvent doesn’t mean that a chemical action occurred. For example, if you put sugar in water as stir, it will dissolve, but the chemical make up of the sugar and the water don’t change. A chemical reaction can be indicated by a drastic change in color or temperature or if a substance precipitate.

Hope this helped :)
6 0
3 years ago
Read 2 more answers
Help me plsss
Yuki888 [10]

Answer:

8.34

Explanation:

1) how much moles of NH₃ are in the reaction;

2) how much moles of H₂ are in the reaction;

3)  the required mass of the H₂.

all the details are in the attachment; the answer is marked with red colour.

Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.

Note2: the suggested solution is not the shortest one.

8 0
3 years ago
If a liter of water is cooled from 50 to 30 what happens to its volume
dangina [55]
In general when you heat up a liquid such as water its volume "increases" as the heat energy causes the water molecules to move leading to more space between molecules causing it to occupy a larger volume.

hope that helps
7 0
3 years ago
Read 2 more answers
Nicotine, a component of tobacco, is composed of C, H, and N. A 7.875-mg sample of nicotine was combusted, producing 21.363 mg o
Gnom [1K]

Answer: The empirical formula for the given compound is C_5H_7N

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, and nitrogen follows:

C_xH_yN_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and nitrogen respectively.

We are given:

Mass of CO_2=21.363mg=21.363\times 10^3g=21363g

Mass of H_2O=6.125g=6.125\times 10^3g=6125g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 21363 g of carbon dioxide, \frac{12}{44}\times 21363=5826.27g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 6125 g of water, \frac{2}{18}\times 6125=680.55 of hydrogen will be contained.

Now we have to calculate the mass of nitrogen.

Mass of nitrogen in the compound = (7875) - (5826.27 + 680.55) = 1368.18 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5826.27g}{12g/mole}=485.52moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{680.55g}{1g/mole}=680.55moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{1368.18g}{14g/mole}=97.73moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0154 moles.

For Carbon = \frac{485.52}{97.73}=4.96\approx 5

For Hydrogen  = \frac{680.55}{97.73}=6.96\approx 7

For Nitrogen = \frac{97.73}{97.73}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 5 : 7 : 1

Hence, the empirical formula for the given compound nicotine is C_5H_7N_1=C_5H_7N

7 0
3 years ago
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