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Vsevolod [243]
3 years ago
8

Ou are driving on the highway at a speed of 40 m/s (which is over the speed limit) when you notice a cop in front of you. To avo

id a ticket, you press on the brake and slow to a speed of 30 m/s over the course of 5 seconds. What is the acceleration of the car? SHOW WORK OR GET REPORTED(have 5 accounts)
What is your car's initial velocity?

What is your car's final velocity?

How long does it take the car to slow down?

Write the equation you will use to solve this problem.

What is the acceleration of your vehicle?
+ 2.0 m/s^2
- 2.0 m/s^2
+ 8.0 m/s^2
- 6.0 m/s^2
Physics
1 answer:
harina [27]3 years ago
7 0

Answer:

What is the acceleration of your vehicle?

+ 2.0 m/s^2✔

- 2.0 m/s^2

+ 8.0 m/s^2

- 6.0 m/s^2

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football game customarily begins with a coin toss to determine who kicks off. The referee tosses the coin up with an initial spe
LuckyWell [14K]

Answer:

1.28 m

Explanation:

You are given the initial speed that is 5 m/s. Since the coin is sent upwards, this means that the speed is positive according to the co-ordinate system in the y axis. Additionally, there is the gravity that curbs the coin in the opposite direction making the final speed becomes zero at the highest point, so the gravity takes negative sign.

So, from the explanation we have:

Vo = 5 m/s

V = 0 m/s

a = -9.8 m/s^2

so, we use the following equation to find y (hight)

V^2 = Vo^2 + 2ay

y = V^2 - Vo^2 / 2a

y = (0 m/s)^2 - (5 m/s)^2 / 2*(-9.8 m/s^2)

y = - (25 m^2 / s^2) / -19.6 m /s^2

y = 1.28 m

3 0
3 years ago
Certain suv ads claim that their vehicles can climb a slope of 45?. what is the minimum coefficient of static friction between t
kotykmax [81]
First, you make a force body diagram to illustrate the problem. Then, apply Newton's laws of motion.

Summation of forces along the y-direction:

F = 0 (bodies at equilibrium) = Normal force - weight*cos45 = 0
Normal force = wcos45

Summation of forcesalong the x-direction:

F = 0 (bodies at equilibrium) = Frictional force - weight*sin45 = 0
x*Normal force - weight*sin45 = 0   (let x be the min coeff of static friction)
x*weight*cos45 = weight*sin 45
x = sin45/cos45 = 1

Therefore, the minimum coefficient of static friction must be 1.
8 0
3 years ago
Your dog is running around the grass in your back yard. He undergoes successive displacements 3.46 m south, 7.96 m northeast, an
vodka [1.7K]

Answer:

8.84 m

Explanation:

Resolving in both x and y components and taking N and E as positive, S and W as negative then

<u>X-component</u>

7.96cos 45^{\circ}-14.2=-8.571430022m

<u>Y-component</u>

-3.46+7.96sin45^{\circ}=2.168569978

Resultant= \sqrt {x^{2}+y^{2}}=\sqrt {(-8.571430022)^{2}+2.168569978^{2}}=8.841499215m\approx 8.84 m

6 0
4 years ago
S A block of mass M is connected to a spring of mass m and oscillates in simple harmonic motion on a frictionless, horizontal tr
Elina [12.6K]

The period of oscillation is T = 2 * pi * sqrt ( ( m2/3 + m1) / k )

<h3>What is period of oscillation?</h3>

This is the time in seconds it takes to complete one oscillation. where an oscillation is a repetitive to and fro motion. period if the inverse of frequency and both are basic when calculation motion in simple harmonic motion.

The period of oscillation is given as T

T = 2 * pi * sqrt ( m / k )

where

m = mass on this case mass of the spring will be inclusive to the mass of the block such that we have:

m1 = mass of the block

m2 = mass pf the spring

k = force constant of the spring

including the two masses to the period gives

T = 2 * pi * sqrt ( ( m2/3 + m1) / k )

Read more on period of oscillation here: brainly.com/question/22499336

#SPJ4

7 0
2 years ago
Guys help me please gr5 science pls help
Stolb23 [73]

Answer:

just google it.

Explanation:

Because its easier

7 0
4 years ago
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