-log(9)= -0.954
______________
Answer: The equilibrium constant, 
, for the reaction is 0.061.
Explanation:
Initial concentration of 
= 
Equilibrium concentration of = 
The given balanced equilibrium reaction is,
Initial conc. 0.039 M 0 M 0 M
At eqm. conc. (0.039-x) M (x) M (x) M
Given : (0.039-x) = 0.012
x = 0.027
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCl_2%5D%5Ctimes%20%5BPCl_3%5D%7D%7B%5BPCl_5%5D%7D)
Now put all the given values in this expression, we get :
The equilibrium constant, , for the reaction is 0.061.
Answer: 0.45 J / g °C
Explanation: solution attached.
Heat is equal to the product of mass, specific heat and change in temperature.
Q= mc∆T
Derive the equation to find c
c = Q / m∆T substitute the values
c = 21.6 J / 2.0g ( 24°C - 5°C)
c = 0.45 J / g ° C
The question correctly reads:
The reaction between nitrogen and hydrogen to produce ammonia is described as an equilibrium reaction. What substances are present in the reaction mixture when equilibrium has been obtained?
3H2 + N2 = 2NH3
N2
H2
NH4+
NH3
Answer:
N2,H2,NH3
Explanation:
Equilibrium is said to be attained when the rate of forward reaction equals the rate of reverse reaction. That is forward and reverse reactions occur at the same rate. The rate at which reactants are reformed, is the same rate at which products are formed. Hence at equilibrium both reactants and products are present in the reaction mixture. This implies that nitrogen, hydrogen and ammonia are all present in the reaction mixture at equilibrium.
Definitely, the more you research into something the more information on it you’ll get, they could very well realize that with the new information their old faces were incorrect
