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3 years ago

How is strong wind caused

Chemistry

1 answer:

Nana76 [90]3 years ago

4 0

Answer:

Heavy winds are typically formed by atmospheric pressure variations, which cause gusts of air to rush in to fill low-pressure zones.

Explanation:

Additionally, wind can result from heavy activity in the jet-stream high in the sky. Finally, large fronts of cold air can also provoke turbulence in the atmosphere.

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Explanation:

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2 years ago

What do electromagnetic waves carry? How are they produced Through which media can they move? Where do they transfer energy? Wha

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3 years ago

6. Three ice cubes are placed inside a glass of hot chocolate. Which of the following best

ycow [4]

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2 years ago

An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average

Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = $\frac{Displacement }{Change in time}$ = Δx / Δt = $\frac{x2 - x1}{t2 - t1}$

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{2100km }{1000km/h}$

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{1300km }{800km/h}$

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = $\frac{x2 - x1}{t2 - t1}$

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = $\frac{1300 - 2100}{1.625 - 2.1}$

Average velocity = 1684.21 km/h

7 0

3 years ago

WILL MARK BRAINLIEST!!!!

Lyrx [107]

Answer:

5.702 mol K₂SO₄

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Compounds
Moles

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

Step 2: Identify Conversions

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})$
[DA] Divide [Cancel out units]: $\displaystyle 5.7015 \ mol \ K_2SO_4$

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

7 0

3 years ago