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2 years ago

Magsulat sa iyong sailing lyrics na kanta the tune of meron leron sinta

Chemistry

1 answer:

xxMikexx [17]2 years ago

3 0

Answer:

I am sailing

Home again

'Cross the sea

I am sailing

Stormy waters

To be near you

To be free

I am flying

Like a bird

'Cross the sky

I am flying

Passing high clouds

To be with you

To be free

Can you hear me, can you hear me

Through the dark night, far away

I am dying, forever crying

To be with you, who can say

Can you hear me, can you hear me

Through the dark night far away

I am dying, forever crying

To be with you, who can say

We are sailing, we are sailing

Home again

'Cross the sea

We are sailing

Stormy waters

To be near you

To be free

Oh Lord, to be near you, to be free

Oh Lord

Explanation:

I hope this is the right one

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Answer:

The pH of the solution is basic

Explanation:

as one of the characteristics of the base is to increase the OH concentration in a solution so if the solution has low concentration of OH this means that the solution is basic

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3 years ago

givi [52]

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3 years ago

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3 years ago

What pressure is required to compress 156.0 liters of air at 2.00 atmosphere into a cylinder

garik1379 [7]

Answer:

option B.

Explanation:

Given,

V₁ = 156 L

P₁ =2 atm

Now, in the cylinder

P₂ = ?

V₂ = 36

Using relation between pressure and volume

$\dfrac{P_1}{V_2}=\dfrac{P_2}{V_1}$

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3 years ago

Hard water often contains dissolved Ca2+ and Mg2+ ions. One way to soften water is to add phosphates. The phosphate ion forms in

avanturin [10]

<span>5.5×10−2M in calcium chloride and 8.0×10−2M in magnesium nitrate.
What mass of sodium phosphate must be added to 1.5L of this solution to completely eliminate the hard water ion

1) Content of Ca (2+) ions

Calcium chloride = CaCl2

Ionization equation: CaCl2 ---> Ca (2+) + 2 Cl (-)

=> Molar ratios: 1 mol of CaCl2 : 1 mol Ca(2+) : 2 mol Cl(-)

Calculate the number of moles of CaCl2 in 1.5 liters of 5.5 * 10^-2 M solution

M = n / V => n = M*V = 5.5 * 10^ -2 M * 1.5 l = 0.0825 mol CaCl2

=> 0.0825 mol Ca(2+)

2) Number of phosphate ions needed to react with 0.0825 mol Ca(2+)

formula of phospahte ion: PO4 (3-)

molar ratio: 2PO4(3-) + 3Ca(2+) = Ca3 (PO4)2

Proportion: 2 mol PO4(3-) / 3 mol Ca(2+) = x / 0.0825 mol Ca(2+)

=> x = 0.0825 coml Ca(2+) * 2 mol PO4(3-) / 3 mol Ca(2+) = 0.055 mol PO4(3-)

3) Content of Mg(2+) ions

Ionization equation: Mg (NO3)2 ----> Mg(2+) + 2 NO3 (-)

Molar ratios: 1 mol Mg(NO3)2 : 1 mol Mg(2+) + 2 mol NO3(-)

number of moles of Mg(NO3)2 in 1.5 liter of 8.0 * 10^-2 M solution

n = M * V = 8.0 * 10^ -2 M * 1.5 liter = 0.12 moles Mg(NO3)2

ions of Mg(2+) = 0.12 mol Mg(NO3)2 * 1 mol Mg(2+) / mol Mg(NO3)2 = 0.12 mol Mg(2+)

4) Number of phosphate ions needed to react with 0.12 mol Mg(2+)

2PO4(3-) + 3Mg(2+) = Mg3(PO4)2

=> 2 mol PO4(3-) / 3 mol Mg(2+) = x / 0.12 mol Mg(2+)

=> x = 0.12 * 2/3 mol PO4(3-) = 0.16 mol PO4(3-)

5) Total number of moles of PO4(3-)

0.055 mol + 0.16 mol = 0.215 mol

6) Sodium phosphate

Sodium phosphate = Na3(PO4)

Na3PO4 ---> 3Na(+) + PO4(3-)

=> 1 mol Na3PO4 : 1 mol PO4(3-)

=> 0.215 mol PO4(3-) : 0.215 mol Na3PO4

mass in grams = number of moles * molar mass

molar mass of Na3 PO4 = 3*23 g/mol + 31 g/mol + 4*16 g/mol = 164 g/mol

=> mass in grams = 0.215 mol * 164 g/mol = 35.26 g

Answer: 35.26 g of sodium phosphate
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3 years ago

Magsulat sa iyong sailing lyrics na kanta the tune of meron leron sinta​

Magsulat sa iyong sailing lyrics na kanta the tune of meron leron sinta