B. The bus is going forward and suddenly stopped.
Answer:
NO
Explanation:
Acceleration is change in velocityΔv in respect to timeΔt
so if the velocity of the car is greater than the truck it does not mean that the car acceleration is greater than the truck.
Sometimes with constant velocity it means no accelaration ,but the truck may have accelaration
so, higher velocity of the car does not mean higher acceleration
] Ceres is composed of rock and ice and is estimated to comprise approximately one third of the mass of the entire asteroid belt. Ceres is the only object in the asteroid belt known to be rounded by its own gravity (though detailed analysis was required to exclude 4 Vesta). From Earth, the apparent magnitude of Ceres ranges from 6.7 to 9.3, peaking once every 15 to 16 months,[21]hence even at its brightest it is too dim to be seen with the naked eye except under extremely dark skies.
Answer:
inertia
Explanation:
The property of matter that will keep the body in motion when the car comes to a halt is the inertia force.
Inertia is the ability of a body to remain in static position. It is the tendency to remain in a stable condition where there is no motion.
- Newton's first law is the law of inertia and it states that a body remain in a state of rest or of uniform motion unless acted upon by an external force.
- The ability to remain in state of rest by a body is predicated on the force of inertia.
348.34 m/s. When Superman reaches the train, his final velocity will be 348.34 m/s.
To solve this problem, we are going to use the kinematics equations for constant aceleration. The key for this problem are the equations
and
where
is distance,
is the initial velocity,
is the final velocity,
is time, and
is aceleration.
Superman's initial velocity is
, and he will have to cover a distance d = 850m in a time t = 4.22s. Since we know
,
and
, we have to find the aceleration
in order to find
.
From the equation
we have to clear
, getting the equation as follows:
.
Substituting the values:

To find
we use the equation
.
Substituting the values:
