5.451 X 10³ kg of sodium carbonate must be added to neutralize 5.04×103 kg of sulfuric acid solution.
<u>Explanation</u>:
- Sodium carbonate is used to neutralized sulfuric acid, H₂SO₄. Sodium carbonate is the salt of a strong base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:
Na₂CO₃ + H₂SO₄ ----> Na₂SO₄ + H₂CO₃
- From a balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of H₂SO₄.
- Molar mass of Na₂CO₃= 106 g/mol = 0.106 kg/mol and Molar mass of H₂SO₄= 98 g/mol = 0.098 kg/mol.
- To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, To neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is = 5.451 X 10³ kg.
Answer:
30%
Explanation:
I don't know how to explain but I learnt this yesterday
Answer:
1.1713 moles
Explanation:
RFM of N2O5= (14*2)+(16*4)=108
Moles of N2O5= Mass/RFM= 63.25/108= 0.5856 moles
Mole ratio of N2O5:NO2 = 2:4
Therefore moles of NO2= 4/2*0.5856= 1.1713 moles
Water was bored. He decided to go through the water cycle. He flew in the air as gas, then condensed into water again, and then rolled down into a river, only to find out that he would be stuck doing it forever
. The end
