Answer:
30gtts/min
Explanation:
To solve this problem we need to divide the volume(mL) and time(min) then multiply by the drop factor. Note that 1hr = 60min.
120/60 * 15 = 30gtts/min
Best of Luck!
<span>the element that requires the least amount of energy to remove the outer-most electron from a gaseous atom in the ground state is s</span><span>odium</span>
Chose 3 you know this because you will need heat..
c both of the above the oh ranges from 0 to 14 a ph of 7 is neutral
