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Marianna [84]
2 years ago
12

1. How many moles of NaCl would be contained in .750 L solution with a molarity of 0.45M?

Chemistry
2 answers:
Evgesh-ka [11]2 years ago
5 0
Formula of Molarity =

Molarity = no. of moles /volume of solution in L

Given, 0.45M= no. of moles/0.750L
Therefore, no. of moles = 0.45M x 0.750L= 0.3375
yarga [219]2 years ago
4 0

Answer:

\boxed {\boxed {\sf 0.3375 \ mol \ NaCl}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

M=\frac{moles \ of \ solute }{liters \ of \ solution}

We know the molarity is 0.45 M and there are 0.750 liters of solution. The solute is NaCl (sodium chloride). We can substitute the values into the formula.

0.45 \ M = \frac{ moles \ of \ NaCl}{ 0.750 \ L }

The molarity (M) can also be represented by mol/L

0.45 \ mol/L = \frac{ moles \ of \ NaCl}{ 0.750 \ L }

We are solving for the moles of solute, so we must isolate the numerator. It is being divided by 0.750 liters. The inverse operation is multiplication, so multiply both sides of the equation by 0.750 L.

0.750 \ L * 0.45 \ mol/L = \frac{ moles \ of \ NaCl}{ 0.750 \ L }*0.750 \ L

The liters will cancel out.

0.750  * 0.45 \ mol = { moles \ of \ NaCl}

0.3375 \ mol \ = moles \ of NaCl

There are <u>0.3375 moles of NaCl</u> in a 0.750 liter solution with a molarity of 0.45 M.

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tekilochka [14]

Answer:

The amount of drug left in his body at 7:00 pm is 315.7 mg.

Explanation:

First, we need to find the amount of drug in the body at 90 min by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

λ: is the decay constant = ln(2)/t_{1/2}

t_{1/2}: is the half-life of the drug = 3.5 h

N(t): is the quantity of the drug at time t

N₀: is the initial quantity

After 90 min and before he takes the other 200 mg pill, we have:

N_{t} = 200e^{-\frac{ln(2)}{3.5 h}*90 min*\frac{1 h}{60 min}} = 148.6 mg

Now, at 7:00 pm we have:

t = 7:00 pm - (5:00 pm + 90 min) = 30 min

N_{t} = (200 + 148.6)e^{-\frac{ln(2)}{3.5 h}*30 min*\frac{1 h}{60 min}} = 315.7 mg    

Therefore, the amount of drug left in his body at 7:00 pm is 315.7 mg (from an initial amount of 400 mg).

I hope it helps you!

3 0
2 years ago
Three isotopes of argon occur in nature – 36 18Ar, 38 18Ar, 40 18Ar. Calculate the average atomic mass of argon to two decimal p
likoan [24]

Answer: 3) 39.96 amu

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% abundance of isotope Ar- 36= 0.337% = \frac{0.337}{100}=3.37\times 10^{-3}

Mass of isotope Ar- 38 = 37.96 amu

% abundance of isotope 2 = 0.063 % = \frac{0.063}{100}=6.3\times 10^{-4}

Mass of isotope Ar- 40 = 39.96 amu

% abundance of isotope 2 = 99.600 % = \frac{99.600}{100}=0.996

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(35.97\times 3.37\times 10^{-3})+(37.96\times 6.3\times 10^{-4})+(39.96\times 0.996)]

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As a result, kinetic energy of molecules increases and they collide rapidly. Hence, solid state of water changes into liquid state and upon excessive heating liquid state of water changes into vapor state.

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