Answer:
Theoretical yield: 13.9 g
Percent yield: 94 %
Explanation:
The reaction is:
CaCO₃ → CaO + CO₂
We see that the reaction is correctly balanced.
1 mol of calcium carbonate can decompose to 1 mol of calcium oxide and 1 mol of carbon dioxide.
We convert the mass to moles: 24.8 g . 1mol / 100.08g = 0.248 moles
As ratio is 1:1, 0.248 moles of salt can decompose to 1 mol of oxide.
We convert the moles to mass: 0.248 mol . 56.08g /1mol = 13.9 g
That's the theoretical yield.
To determine the percent yield we think:
(Determined yield / Theoretical yield) . 100 → (13.1 / 13.9) . 100 = 94 %
The engine ran for 10 second
its 40
I just took the test right now to get this answer
