Why do I eat Takis please

Functional and nonfunctional requirements documents are used to _____.

Fiesta28 [93]

Answer:

Non-functional requirements when defined and executed well will help to make the system easy to use and enhance the performance

Explanation:

7 0

3 years ago

What is the average speed of a car that travels 80km in 1.5 hours

DanielleElmas [232]

Answer:53.33km/hr.

Explanation:

Average speed =

distance traveled/time taken

Average speed =80km/1.5hr=53.33km/hrs

5 0

4 years ago

Read 2 more answers

Describe the risks associated with their working environment (such as the tools, materials and equipment that they use, spillage

Llana [10]

The risks which are associated with such working environment and not reporting accidental breakages of tools is pollution and damage to the body system of individuals.

This is defined as the possibility of something causing a bad event to occur and is common in workplace when tools are left carelessly which can cause injuries etc.

In the case of a working environment with oil spills, it can lead to slipping of the individuals present in the area and not reporting accidental breakages of tools or equipment could also lead to pollution and different forms of accident which thereby making it the most appropriate choice in this context.

Read more about Risk here brainly.com/question/1224221

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3 0

2 years ago

1. A gas pressure difference is applied to the legs of a U-tube manometer filled with a liquid with S = 1.5. The manometer readi

julia-pushkina [17]

Answer:

1) The pressure difference is 4.207 kilopascals.

2) 2.5 pounds per square inch equals 5.093 inches of mercury and 5.768 feet of water.

Explanation:

1) We can calculate the gas pressure difference from the U-tube manometer by using the following hydrostatic formula:

$\Delta P = \frac{S\cdot \rho_{w}\cdot g \cdot \Delta h}{1000}$ (Eq. 1)

Where:

$S$ - Relative density, dimensionless.

$\rho_{w}$ - Density of water, measured in kilograms per cubic meter.

$g$ - Gravitational acceleration, measured in meters per square second.

$\Delta h$ - Height difference in the U-tube manometer, measured in meters.

$\Delta P$ - Gas pressure difference, measured in kilopascals.

If we know that $S = 1.5$ , $\rho_{w} = 1000\,\frac{kg}{m^{3}}$ , $g = 9.807\,\frac{m}{s^{2}}$ and $\Delta h = 0.286\,m$ , then the pressure difference is:

$\Delta P = \frac{1.5\cdot \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.286\,m)}{1000}$

$\Delta P = 4.207\,kPa$

The pressure difference is 4.207 kilopascals.

2) From Physics we remember that a pound per square unit equals 2.036 inches of mercury and 2.307 feet of water and we must multiply the given pressure by corresponding conversion unit: ( $p = 2.5\,psi$ )

$p = 2.5\,psi\times 2.037\,\frac{in\,Hg}{psi}$

$p = 5.093\,in\,Hg$

$p = 2.5\,psi\times 2.307\,\frac{ft\,H_{2}O}{psi}$

$p = 5.768\,ft\,H_{2}O$

2.5 pounds per square inch equals 5.093 inches of mercury and 5.768 feet of water.

4 0

4 years ago

A 220-V electric heater has two heating coils that can be switched such that either coil can be used independently or the two ca

Nana76 [90]

Answer:

The resistances of both coils are 131.7 Ω and 29.64 Ω.

Explanation:

Since, there are two coils, they can be used independently or in series or parallel. The power is given as:

Power = P = VI

but, from Ohm's Law:

V = IR

I = V/R

therefore,

P = V²/R

R = V²/P

Hence, the resistance (R) and (P) are inversely proportional. Therefore, the maximum value of resistance will give minimum power, that is, 300 W. And the maximum resistance will be in series arrangement, as in series the total resistance gets higher than, any individual resistance.

Therefore,

Rmax = V²/Pmin = R1 + R2

R1 + R2 = (220 V)²/300 W

R1 + R2 = 161.333 Ω ______ en (1)

Similarly, the minimum resistance will give maximum power. And the minimum resistance will occur in parallel combination. Because equivalent resistance of parallel combination is less than any individual resistance.

Therefore,

(R1 R2)/(R1 + R2) = (220 V)²/2000 W

using eqn (1), we get:

(R1 R2) / 161.333 Ω = 24.2 Ω

R1 R2 = 3904.266 Ω²

R1 = 3904.266 Ω²/R2 _____ eqn (2)

Using this value of R1 in eqn (1), we get:

3904.266/R2 +R2 = 161.333

(R2)² - 161.333 R2 +3904.266 = 0

Solving this quadratic eqn we get two values of R2 as:

R2 = 131.7 Ω OR R2 = 29.64 Ω

when ,we substitute these values in eqn (1) to find R1, we get get the same two values as R2, alternatively. This means that the two coils have these resistance, and the order does not matter.

<u>Therefore, the resistance of both coils are found to be 131.7 Ω and 29.64 Ω</u>

7 0

3 years ago