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The acronym STP in chemistry stands for Standard Temperature and Pressure. At STP, the temperature will be 273.15 Kelvin (0°C or 32°F) and one mole of gas will occupy 22.4 liters of volume. Standard pressure is set at 1 atm. STP measurements are often used to solve the ideal gas formula (PV = nRT).
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Answer:
Moles = 0.5 mol
Solution:
Moles is related to mass as follow,
Moles = Mass / M.mass ----- (1)
Where;
Mass = 50 g
M.mass = Ca (40) + C (12) + O₃ (16)₃ = 100 g/mol
Putting values in equation 1,
Moles = 50 g ÷ 100 g.mol⁻¹
Moles = 0.5 mol
Answer:
This question is incomplete. The completed question is below
Procedure
1. Read and complete a lab safety form.
2. Place about 50 copper pellets into a plastic petri dish. Place the cover on the dish, and secure it with tape.
3. Hold the dish by the edges. Gently vibrate the dish from side to side no more than 1–2 mm. Observe the pellets. Record your observations in your Science Journal.
4. Repeat step 3, vibrating the dish less than 1 cm from side to side.
5. Repeat step 3, vibrating the dish 3–4 cm from side to side.
if the pellets represent particles in matter, what do you think the shaking represents?
Explanation:
This procedure seeks to illustrate the "properties" of particles in matter. The shaking of the pellets represents the movement of the particles of matter (which occurs in liquids and gases). This is because the movement of particles in a liquid and gaseous state freely moves around (reason the petri-dish was vibrated so the pellet particles which serve as the liquid/gaseous particles can move freely).
NOTE: The particles in a solid have a highly restricted movement (or no movement) because of the compact nature of the particles within the solid.
The balanced equation for the reaction is as follows
8SO₂ + 16H₂S ---> 3S₈ + 16H₂O
stoichiometry of SO₂ to H₂S is 8:16
we have been given 77.0 g of each reactant
the reactants react according to molar ratio in other words according to the stoichiometry
8 mol of SO₂ reacts with 16 mol of H₂S
number of SO₂ moles present - 77.0 g / 64 g/mol = 1.20 mol
number of H₂S moles present - 77.0 g / 34 g/mol = 2.26 mol
we need to find the limiting reactant
limiting reactant is fully used up in the reaction
amount of product formed depends on amount of limiting reactant present
if SO₂ is the limiting reactant
if 8 mol of SO₂ reacts with 16 mol of H₂S
then 1.20 mol of SO₂ reacts with - 16/8 x 1.20 mol = 2.40 mol of H₂S
but only 2.26 mol of H₂S are present
which means H₂S is the limiting reactant
then amount of S₈ formed depends on H₂S present
stoichiometry of H₂S to S₈ is 16:3
16 mol of H₂S forms 3 mol of S₈
then 2.26 mol of H₂S forms - 3/16 x 2.26 = 0.424 mol
mass of S₈ formed - 0.424 mol x 256 g/mol = 108.5 g
108.5 g of S₈ is formed