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lys-0071 [83]
3 years ago
13

A 3.5 L sample of gas at 25oC has an initial pressure of 86.7 kPa. The pressure of the gas decreases to 56.7 kPa as the gas expa

nds to volume of 8.00 L. What is the new temperature of the gas?
1. 445 K
2. 199 K
3. 310 K
4. 85.3 K
Chemistry
1 answer:
katrin2010 [14]3 years ago
8 0

Answer:

445K

Explanation:

according to universal gas theoreme, p1v1/T1=p2v2/T2

therefore, T2=(56.7×8×298)/(3.5×86.7)

≈445K

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How do I solve this?
Xelga [282]

Answer:

Explanation:

When you divide exponentials, you subtract the powers. For the numbers infront, just use a basic calculator for.

7.95/6.02 = 1.32

10^22/10^23 = 10^-1

1.32 x 10^-1 is your answer

7 0
3 years ago
Of the following substances, ________ has the highest boiling point. Of the following substances, ________ has the highest boili
kolezko [41]

Answer:

Of the following substances, <u>PCl₃</u> has the highest boiling point

Explanation:

The given substances and their boiling point from online resources are;

Krypton, Kr, boiling point = -153.4°C

Chlorine gas, Cl₂, boiling point = -34.6°C

Borane, BH₃, (transient compound), boiling point of the dimer it forms B₂H₆ = -164.85°C

Methane, CH₄, boiling point = -161.6°C

Phosphorus trichloride, PCl₃, boiling point = 76.1°C

Therefore, given that PCl₃ is a volatile liquid at room temperature, while the other substances are gases and that PCl₃ has the highest boiling point of all the substances of 76.1°C, the substance with the highest boiling point is PCl₃.

5 0
3 years ago
The number of electrons is not equal to number protons if...?
sineoko [7]

Answer:

the answer is not correct

3 0
3 years ago
The three naturally occurring isotopes of potassium are 39K, 38.963707u; 40K, 39.963999u; and 41K.The percent natural abundances
sweet-ann [11.9K]

Answer:

The isotopic mass of 41K is 40.9574 amu

Explanation:

Step 1: Data given

The isotopes are:  

39K with an isotopic mass of 38.963707u and natural abundance of 93.2581%

40K with an isotopic mass of 39.963999u

41K wit natural abundance of 6.7302 %

Average atomic mass =39.098 amu  

Step 2: Calculate natural abundance of 40 K

100 % - 93.2581 % - 6.7302 %

100 % = 0.0117 %

Step 3: Calculate isotopic mass of 41K

39.098 = 38.963707 * 0.932581 + 39.963999 * 0.000117 + X * 0.067302

39.098 = 36.33681 + 0.0046758 +  X * 2.067302

X = 40.9574 amu

The isotopic mass of 41K is 40.9574 amu

8 0
4 years ago
The diagram shows the box for an element in the periodic
mr_godi [17]

Answer: A 13

Explanation: hope this helps!

6 0
3 years ago
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