Answer:
18 g
Explanation:
Step 1: Write the balanced equation
2 Al + 6 HCl ⇒ 2 AlCl₃ + 3 H₂
Step 2: Calculate the moles of Al
The molar mass of Al is 26.98 g/mol.
28.1 g × 1 mol/26.98 g = 1.04 mol
Step 3: Calculate the moles of HCl
46 mL of 1 M HCl react.
0.046 L × 1 mol/L = 0.046 mol
Step 4: Determine the limiting reactant
The theoretical molar ratio of Al to HCl is 2:6 = 0.33:1.
The real molar ratio of Al to HCl is 1.04:0.046 = 22.6:1
According to this, the limiting reactant is HCl.
Step 5: Calculate the mass of AlCl₃ generated from 0.046 moles of HCl
The molar ratio of HCl to AlCl₃ is 6:2. The molar mass of AlCl₃ is 133.34 g/mol.
0.046 mol HCl × 6 mol HCl/2 mol AlCl₃ × 133.34 g AlCl₃/1 mol AlCl₃ = 18 g AlCl₃
Answer:
remains constant regardless of the pH
Explanation:
The pH refers to the hydrogen potential or hydrogen power that states the aqueous solution acidity. It varies from 0 to 14. The higher pH values denotes more basic solutions while on the other hand, the lower pH values denote more acidic
An acidic solution refers to a solution at which the hydrogen ions concentration is more than the hydroxide ions concentration
Therefore the ion product of water remains constant as the value of both hydrogen ions and hydroxide ions is relatively small as non-dissociated water concentration would remain the same.
Hence, the second option is correct
Explanation:
An F-center, Farbe center or color center is a type of crystallographic defect in which an anionic vacancy in a crystal lattice is occupied by one or more unpaired electrons. Electrons in such a vacancy tend to absorb light in the visible spectrum such that a material that is usually transparent becomes colored.
Answer:
One ring is present.
Explanation:
The degree of unsaturation or double bond equivalents(DBE) can be determined by using a formula. This formula gives us the number of rings and / pi bonds.
As mentioned in the problem the number of pi bond is one so if we calculate the DBE this will give us the number of rings by subtracting one from DBE.
Where
C = number of carbon atoms
X = number of halogens
N = number of nitrogen
H = number of hydrogen
Thus the number of rings will be:
The question is incomplete, here is the complete question:
Consider the following reaction:
In the first 15.0 s of the reaction, 1.9×10⁻² mol of O₂ is produced in a reaction vessel with a volume of 0.480 L . What is the average rate of the reaction over this time interval?
<u>Answer:</u> The average rate of appearance of oxygen gas is
<u>Explanation:</u>
We are given:
Moles of oxygen gas =
Volume of solution = 0.480 L
Molarity is calculated by using the equation:
So,
The given chemical reaction follows:
The average rate of the reaction for appearance of is given as:
Or,
where,
= final concentration of oxygen gas = 0.0396 M
= initial concentration of oxygen gas = 0 M
= final time = 15.0 s
= initial time = 0 s
Putting values in above equation, we get:
Hence, the average rate of appearance of oxygen gas is