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lys-0071 [83]
3 years ago
13

A 3.5 L sample of gas at 25oC has an initial pressure of 86.7 kPa. The pressure of the gas decreases to 56.7 kPa as the gas expa

nds to volume of 8.00 L. What is the new temperature of the gas?
1. 445 K
2. 199 K
3. 310 K
4. 85.3 K
Chemistry
1 answer:
katrin2010 [14]3 years ago
8 0

Answer:

445K

Explanation:

according to universal gas theoreme, p1v1/T1=p2v2/T2

therefore, T2=(56.7×8×298)/(3.5×86.7)

≈445K

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Consider the titration of 42.5 mL of 0.193 M HCl with 0.125 M KOH. Calculate the pH of the resulting solution after the followin
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Answer:

See explanation

Explanation:

Dilution law= C1V1=C2V2.

Where C is the concentration in mol per dm cube and V= volume in dm cube.

From the questions the parameters given are; V= 42.5ZmL, concentration or molarity of HCl= 0.193M and the molarity of KOH = 0.125M.

(a). At 0mL where the base KOH has not been added yet.

Moles of HCl = molarity × volume.

Moles of HCl = 0.193 × 42.5/1000

Moles of HCl= 0.00820205

pH=- log 0.0082025

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Approximately, pH=2.1.

(b). At 3mL of 0.125M KOH

3/1000 × 0.125 mol/L

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= 0.000375 moles KOH

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42.5/1000 × 0.193 mol/L

= 0.0082025

Final volume= 3mL+42.5mL= 45.5 ml

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= 0.1720

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(c). 5mL of 0.125M KOH

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= 0.005×0.125

= 0.000625 mol KOH

42.5/1000 × 0.193 mol/L

= 0.0082025 mol

Final volume= 5mL + 42.5= 47.5 mL.

0.0082025-0.000625= 0.0076

Final [HCl] = 0.0076/0.0475

= 0.16

pH= -log 0.16

pH= 0.79.

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