Hello!
1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?
- <u><em>We have the following data:</em></u>
Vo (initial volume) = 1.00 L
V (final volume) = 473 mL → 0.473 L
Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)
P (final pressure) = ? (in atm)
- <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>
<u><em>Answer: </em></u>
<u><em>The new pressure of the gas is 2.11 atm </em></u>
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Put it in a beaker. Use a smaller beaker filled half way with ice and water and place in the larger one. It should be about an inch or two above the mixture. Heat over a Bunsen burner and the naphthalene will deposit on the bottom of smaller beaker.
And in this way, nephthalene be separated from the mixture of KBR and sand.
Answer:
Mass = 1274 .64 g it would be option C if it is converted into kilogram
1274 .64 / 1000 = 1.27 Kg
Explanation:
Given data:
Number of moles of C₂₀H₄₂ = 4.52 mol
Molar mass of carbon = 12 g/mol
Molar mass of hydrogen = 1.0 g/mol
Mass of C₂₀H₄₂ = ?
Solution:
Number of moles = mass / molar mass
Molar mass = 20× 12 + 42× 1.0 = 282 g/mol
Now we will put the values in formula:
Number of moles = mass / molar mass
4.52 mol = mass / 282 g /mol
Mass = 4.52 mol × 282 g/mol
Mass = 1274 .64 g
Answer:
6.25 L
Explanation:
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!
