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8090 [49]
3 years ago
11

6. Jim wishes to push a 100. N wood crate across a wood floor.What is the minimum horizontal force that would be required to sta

rt the crate moving?
Physics
2 answers:
sergejj [24]3 years ago
7 0
I want to say the answer is 42N
Usimov [2.4K]3 years ago
5 0

Answer:

50 N

Explanation:

The minimum horizontal force required to start the crate moving must be equal to the maximum force of static friction that acts between the floor and the crate.

The maximum force of static friction is given by:

F_f = \mu N

where

\mu is the coefficient of static friction

N is the normal reaction exerted by the floor on the crate.

For wood-wood, as in this case, the maximum coefficient of static friction is about \mu=0.5.

For a horizontal surface, the normal reaction is equal to the weight of the object, so in this case N=100 N. Therefore, the minimum horizontal force required will be:

F=F_f = \mu N=(0.5)(100 N)=50 N

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<span>f(x) = 5.05*sin(x*pi/12) + 5.15

   First, you need to determine the period of the function. The period will be the time interval between identical points on the sinusoidal function. For this problem, the tide is rising and at 5.15 at midnight for two consecutive days. So the period is 24 hours. Over that 24 hour period, we want the parameter passed to sine to range from 0 to 2*pi. So the scale factor for x will be 2*pi/24 = pi/12 which is approximately 0.261799388. The next thing to note is the magnitude of the wave. That will simply be the difference between the maximum and minimum values. So 10.2 ft - 0.1 ft = 10.1 ft. And since the value of sine ranges from -1 to 1, we need to divide that magnitude by 2, so 10.1 ft / 2 = 5.05 ft.

   So our function at this point looks like f(x) = 5.05*sin(x*pi/12) But the above function ranges in value from -5.05 to 5.05. So we need to add a bias to it in order to make the low value equal to 0.1. So 0.1 = X - 5.05, 0.1 + 5.05 = X, 5.15 = X. So our function now looks like:
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   The final thing that might have been needed would have been a phase correction. With this problem, we don't need a phase correction since at X = 0 (midnight), the value of X*pi/12 = 0, and the sine of 0 is 0, so the value of the equation is 5.15 which matches the given value of 5.15. But if the problem had been slightly different and the height of the tide at midnight has been something like 7 feet, then we would have had to calculate a phase shift value for the function and add that constant to the parameter being passed into sine, making the function look like:
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  where
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   But we don't need it for this problem, so the answer is:
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   Note: The above solution assumes that angles are being measured in radians. If you're using degrees, then instead of multiplying x by 2*pi/24 = pi/12, you need to multiply by 360/24 = 15 instead, giving f(x) = 5.05*sin(x*15) + 5.15</span>
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