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3 years ago

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6. Jim wishes to push a 100. N wood crate across a wood floor.What is the minimum horizontal force that would be required to sta

rt the crate moving?

2 answers:

sergejj [24]3 years ago

7 0

I want to say the answer is 42N

Usimov [2.4K]3 years ago

5 0

Answer:

50 N

Explanation:

The minimum horizontal force required to start the crate moving must be equal to the maximum force of static friction that acts between the floor and the crate.

The maximum force of static friction is given by:

$F_f = \mu N$

where

$\mu$ is the coefficient of static friction

$N$ is the normal reaction exerted by the floor on the crate.

For wood-wood, as in this case, the maximum coefficient of static friction is about $\mu=0.5$ .

For a horizontal surface, the normal reaction is equal to the weight of the object, so in this case $N=100 N$ . Therefore, the minimum horizontal force required will be:

$F=F_f = \mu N=(0.5)(100 N)=50 N$

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3 years ago

Two toroidal solenoids are wound around the same form so that the magnetic field of one passes through the turns of the other. S

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The concept that we need here to give a proper solution is mutual inductance.

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3 years ago

A spinning wheel has a rotational inertia of 2 kg•m². It has an angular velocity of 6.0 rad/s. An average counterclockwise torqu

ira [324]

Answer:

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Explanation:

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$L=I \omega$

where

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7 0

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