Question

A soccer player kicks a ball, changing its momentum by 11\, \dfrac {\text{kg}\cdot \text m}{\text s}11 s kg⋅m ​ 11, start fraction, start text, k, g, end text, dot, start text, m, end text, divided by, start text, s, end text, end fraction. The net force on the ball is 910\,\text N910N910, start text, N, end text.

Answer 1

Answer:

0.012  seconds

Explanation:

The time at which the soccer player maintain contact with the ball is as follows:

Given that

Change in momentum = 11 kg.m.s^-1

The Net force applied = F = 910 N

Now the following formulas should be applied:

For acceleration:

$a = \frac{\triangle v}{\triangle t} \\\\\triangle v = a \triangle t$

For momentum

$\triangle p = m\triangle v\\\\\triangle p = ma\triangle t\\\\\triangle p = f\triangle t\\\\\triangle t = \frac{\triangle p}{F}$

Now

Put  the values to the above formula

= 11 ÷ 910

= 0.012 seconds