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Sloan [31]
3 years ago
13

Who trying to talk?????

Physics
2 answers:
Art [367]3 years ago
7 0

Answer:

Me! :)

Explanation:

Elden [556K]3 years ago
7 0
Well I do have school but sure later tho
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A rain gutter is to be constructed from a metal sheet of width 30 cm by bending up one-third of the sheet on each side through a
GarryVolchara [31]

Answer:

60

Explanation:

The volume of the water carried will be proportional to the cross-sectional area. The cross-section is a trapezoid with height 10sint, where t represents theta. The top of the trapezoid is 10+(2)(10cost), i.e. 10 + 20cost. The base of the trapezoid is 10.

Area of trapezoid = (average of bases) times (height)

= ([10 + (10 +20cost)] / 2 ) 10 sint

= (10 + 10cost)(10sint)

= 100sint + 100sintcost, call this A(t). You need to maximize. So differentiate and set equal to zero.

dA/dt = -100sin(t)^2+100cos(t)+100cos(t)^2 = 0, divide by 100:

-sin(t)^2 + cos(t) + cos(t)^2 = 0, replace sin^2 by 1-cos^2

2cos(t)^2 + cos(t) - 1 = 0, factor

(1+cos(t))(2cos(t)-1)=0, so  

cos(t)=1, t=0 that give a min (zero area) not a max, or

cos(t) = 1/2, so t=60 degrees. This gives the max.

7 0
4 years ago
A particle moves along a straight path through displacement while force acts on it. (Other forces also act on the particle.) Wha
allsm [11]

a) c = 1.85

b) c = 0.8

c) c = 2.33

Explanation:

a)

The displacement of the particle is given by

d=2.2i+cj

While the force applied on the particle is

F=3.2i-3.8 j

So we have a problem in 2-dimensions.

The work done on the particle is given by the scalar product between force and displacement:

W=F\cdot d (1)

Here the work done on the particle is zero, so

W = 0

Therefore from eq(1) we find:

0=(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=7.04\\c=\frac{7.04}{3.8}=1.85

b)

In this problem, the work done on the particle is

W=4.0 J

The force and displacement are still

d=2.2i+cj (displacement)

F=3.2i-3.8 j (force)

Therefore, by calculting the scalar product between force and displacement and equating it to the work done (4.0 J), we find:

W=F\cdot d

4.0 =(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=3.04\\c=\frac{3.04}{3.8}=0.8

c)

In this problem instead, the work done on the particle is negative:

W=-1.8 J

As before, the force and displacement are

d=2.2i+cj (displacement)

F=3.2i-3.8 j (force)

And so again, we calculate the scalar product between  force and displacement and we equate it to the work done on the particle, -1.8 J.

Doing so, we find:

W=F\cdot d

-1.8=(3.2i-3.8j)\cdot (2.2i+c)=7.04-3.8c\\3.8c=8.84\\c=\frac{8.84}{3.8}=2.33

7 0
3 years ago
Which type of wave can only be transmitted through matter?
Doss [256]
I only doing this for points, but i think its c
8 0
3 years ago
Read 2 more answers
A bomb, originally sitting at rest, explodes and during the
Archy [21]

Answer:

opposite

Explanation:

6 0
3 years ago
A ball rolled 10 meters in 2 seconds. Its velocity is m/s
dalvyx [7]

Answer:

velocity is 5m/s

Explanation:

data

d=10m

t=2sec

v=?

from

v=d/t

v=10m/2s

v=5m/s

8 0
3 years ago
Read 2 more answers
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