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3 years ago

ONE EASY QUESTION

Physics

1 answer:

Brrunno [24]3 years ago

8 0

Answer:

its tension force which acts in a string

Explanation:

need a thanks and thats it

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The temperature and pressure at the surface of Mars during a Martian spring day were determined to be -41 oC and 900 Pa, respect

Fittoniya [83]

Answer:

Part a)

$\rho = 0.0205 kg/m^3$

Part b)

$\rho = 1.22 kg/m^3$

So density of atmosphere at Martian Surface is very less than the density at Earth.

Explanation:

Part a)

As per ideal gas equation we know that

$PM = \rho RT$

here we know that Martian atmosphere is equivalent to that of carbon

so we will have

$P = 900 Pa$

$T = 273 - 41 = 232 K$

now we will have

$(900)(0.044) = \rho (8.31)(232)$

$\rho = 0.0205 kg/m^3$

Part b)

Now for the earth surface the density of air is given for

$P = 101.6 kPa$

$T = 18 ^oC$

so we will have

$PM = \rho RT$

$(101.6\times 10^3)(0.029) = \rho(8.31)(273 + 18)$

$\rho = 1.22 kg/m^3$

So density of atmosphere at Martian Surface is very less than the density at Earth.

8 0

3 years ago

Linear Velocity What is the linear velocity in cm>min for any edge point of a 12-cm-diameter CD (compact disc) spinning at 10

daser333 [38]

3,89,988 cm/min is the linear velocity

Given,

Diameter of CD = 12 cm

So, Radius of CD = 6 cm

CD is spinning at 10350 rev/min

Firstly , convert rev/min into rad/min

1 rev = 2π radians

10350 rev/min = 10350 × 2π

= 64998 rad/min

Formula used,

$v=rw$ where,

$v$ is the Linear velocity

$r$ is the radius

$w$ is the angular velocity

$v$ = 6 cm × 64998rad/min

= 3,89,988 cm/min

Thus, linear velocity for any edge point of a 12-cm-diameter CD (compact disc) spinning at 10,350 rev/min is 389988 cm/min.

Learn more about Angular speed here brainly.com/question/540174

#SPJ4

8 0

2 years ago

An object in circular motion has velocity that is constantly changing. The direction of the acceleration is

Keith_Richards [23]

<h2>Answer: Toward the center of the circle.</h2>

This situation is characteristic of the uniform circular motion , in which the movement of a body describes a circumference of a given radius with constant speed.

However, in this movement the velocity has a constant magnitude, but its direction varies continuously.

Let's say $\vec{V}$ is the velocity vector, whose direction is perpendicular to the radius $r$ of the trajectory, therefore the acceleration $\vec{a}$ is directed toward the center of the circumference.