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max2010maxim [7]
3 years ago
7

How do you simplify (25b^6)^-1.5

Mathematics
1 answer:
solniwko [45]3 years ago
4 0

Answer:

\frac{1}{ {25}^{1.5}  {b}^{9} }

Step-by-step explanation:

Use the negative power rule:

{x}^{ - a}  =  \frac{1}{ {x}^{a} }

\frac{1}{(25 {b}^{6})^{1.5}  }

Use multiplication Distributive Property: (xy)^a = x^a y^a.

\frac{1}{ {25}^{1.5}( {b}^{6}) ^{1.5}   }

Use power rule: (x^a)^b = x^ab.

\frac{1}{ {25}^{1.5}  {b}^{9} }

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>1</u><u>/</u><u>25</u><u>^</u><u>1</u><u>.</u><u>5</u><u> </u><u>b</u><u>^</u><u>9</u>

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Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p
GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

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you replace t1 from the first equation in the second equation:

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The points at which the paths  intersect are:

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r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)

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t=1+2t\\\\t=-1

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The graph of the equation below is a circle. What is the length of the radius of the circle? (x - 4)^2 + (y + 12)^2 = 17^2
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The correct answer is:  [D]:  "17" .
______________________________________________________
The radius is:  " 17" .
______________________________________________________
Note:
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The formula/equation for the graph of a circle is:
______________________________________________________
   (x − h)²  +<span> </span> (y − k)² =  r²  ;

in which:  

          " (h, k) " ; are the coordinate of the point of the center of the circle;

           "r" is the length of the "radius" ; for which we want to determine;
_______________________________________________________
We are given the following equation of the graph of a particular circle:
_______________________________________________________

          →  (x − 4)²  +  (y + 12)² =  17² ;

which is in the correct form:

→  " (x − h)²  +  (y − k)² =  r²  " ;

 in which:  " h = 4 " ;

                  " k = -12" ;

                   "r = 17 " ;  which is the "radius" ; which is our answer.

          →  { Note that: "k = NEGATIVE  12" } ;

→  Since the equation <u>for this particular circle</u> contains the expression:             _________________________________________________________    
                      →     "...(y + k)² ..." ;  
         
[as opposed to the standard form:  "...(y − k)² ..." ] ; 
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→  And since the coordinates of the center of a circle are represented by:
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→  which are:  " (4, -12) " ;  (<u>for this particular circle</u>) ; 
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→  And since:  " k = -12 " ;  (<u>for this particular circle</u>) ;
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then: 

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{NOTE:  Since:  "subtracting a negative" is the same as "adding a positive" ;

           →   So;  " [ y − (-12 ] " = " [ y + (⁺ 12) ] " = " (y + 12) "
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           →    Since:  "r  =  17 " ;  

           →  The radius is:  " 17 " ;

          which is:  Answer choice:  [D]:  "17" .
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