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3 years ago

Does anyone know what these three are? I need help!

Physics

1 answer:

VashaNatasha [74]3 years ago

3 0

Answer:

1. A

2. C

3. A

Explanation:

I'm so sorry if I am wrong

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A mass of 148g stretches a spring 6cm. The mass is set in motion from its equlibrium position with a downward velocity of 10cm/s

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Answer:

$u(t)=0.78sin12.78t$

Explanation:

We are given that

Mass,m=148 g

Length,L=6 cm

Velocity,u'(0)=10 cm/s

We have to find the position u of the mass at any time t

We know that

$\omega_0=\sqrt{\frac{g}{L}}=\sqrt{\frac{980}{6}}=12.78 rad/s$

Where g= $980 cm/s^2$

$u(t)=Acos12.78 t+Bsin 12.78t$

u(0)=0

Substitute the value

$A=0$

$u'(t)=-12.78Asin12.78t+12.78 Bcos12.78 t$

Substitute u'(0)=10

$12.78B=10$

$B=\frac{10}{12.78}=0.78$

Substitute the values

$u(t)=0.78sin12.78t$

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2 years ago

A 8.01-nC charge is located 1.87 m from a 4.50-nC point charge. (a) Find the magnitude of the electrostatic force that one charg

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Answer:

Explanation:

Given

$q_1=8.01\ nC$

$q_2=4.50\ nC$

distance between the charges is given by $d=1.87\ m$

Electrostatic force between the charges is given by

$F_{12}=F_{21}=\frac{kq_1q_2}{d^2}$

where k=constant $=9\times 10^{9}$

$F_{12}=F_{21}=\frac{9\times 10^9\times 8.01\times 4.50\times 10^{-18}}{(1.87)^2}$

$F_{12}=F_{21}=92.769\times 10^{-9}\ N$

as both the charges are of similar nature therefore they repel each other

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3 years ago

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The distance between two charged objects is doubled. What happens to the electrostatic force between the two?a)It will double.b)

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Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the separation between the two objects

In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

$F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F$

So, the force will be cut to 1/4 of the original value.

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2 years ago