Answer:
Explanation:
1.
=
* cos
⇒ 16*cos32 ≈ 13.6 m/s (13.56)
2.
=
* sin
⇒ 16* sin32 ≈ 9.4 m/s
3.
=
=
(the g (gravity) depends on the country but i'll take the average g which is 9.2m/s^2)
≈ 3.6677+1.5 ≈ 5.2m
4.
=
=
≈ 23.5m (23.47)
5. -
answer 4 could be wrong, not certain about that one and i don't know 5
Answer:
Distance covered by the train, x = 493.72 meters
Explanation:
It is given that,
Initial speed of the train, u = 80 km/h = 22.22 m/s
Final speed of the train, v = 0 (it stops)
Acceleration of the train,
(it decelerates)
Let x is the distance the train travels from the time the conductor applies the brakes until the train comes to a complete stop. It can be calculated using the kinematic formula as :
![v^2-u^2=2ax](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ax)
![x=\dfrac{v^2-u^2}{2a}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2a%7D)
![x=\dfrac{-(22.22)^2}{2\times -0.5}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-%2822.22%29%5E2%7D%7B2%5Ctimes%20-0.5%7D)
x = 493.72 meters
So, the distance covered by the train from the time the conductor applies the brakes until the train comes to a complete stop is 493.72 meters. Hence, this is the required solution.
Answer:
-0.233 m left of diverging lens and ( 0.12 - 0.233 ) = -113 m left of conversing
and
0.023 m right of diverging lens
Explanation:
given data
focal length f2 = 14 cm = -0.14 m
Separation s = 12 cm = 0.12 m
focal length f1 = 21 cm = 0.21 m
distance u1 = 38 cm
to find out
final image be located and Where will the image
solution
we find find image location i.e v2
so by lens formula v1 is
1/f = 1/u + 1/v ...............1
v1 = 1/(1/f1 - 1/u1)
v1 = 1/( 1/0.21 - 1/0.38)
v1 = 0.47 m
and
u2 = s - v1
u2 = 0.12 - 0.47
u2 = -0.35
so from equation 1
v2 = 1/(1/f2 - 1/u2)
v2 = 1/(-1/0.14 + 1/0.35)
v2 = -0.233 m
so -0.233 m left of diverging lens and ( 0.12 - 0.233 ) = -113 m left of conversing
and
for Separation s = 45 cm = 0.45 m
v1 = 1/(1/f1 - 1/u1)
v1 =0.47 m
and
u2 = s - v1
u2 = 0.45 - 0.47 =- 0.02 m
so
v2 = 1/(1/f2 - 1/u2)
v2 = 1/(-1/0.14 + 1/0.02)
v2 = 0.023
so here 0.023 m right of diverging lens
Answer:
c
Explanation:
plz make me brainliest i have answered