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natulia [17]
3 years ago
14

Give an example of an adaptation.

Chemistry
1 answer:
lana66690 [7]3 years ago
3 0

Never gonna give you up

let you downnnn

never gonna turn around

and hurt youu

never gonna make you cryy

sayyyyy goodbyeeee

tell a lie

or hurt youuuuuuuuuuuuu

ha get rick rolled nerd

goodbye

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__________, a colligative property, is the difference between the freezing temperature of a pure solvent and the freezing point
PilotLPTM [1.2K]
<span>Freezing-point depression.</span>
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3 years ago
Liquid nitrogen, which has a boiling point of −195.79°C, is used as a coolant and as a preservative for biological tissues. Is t
Ray Of Light [21]

Answer:

Explanation:

Entropy is measure of disorder so as we lower the temperature of gas , its entropy decreases .

Hence at - 200°C entropy of nitrogen will be less than that at - 190°C .

At freezing point ,

entropy of fusion  = latent heat / freezing temperature

= .71 kJ / ( 273 - 210 )

= 710 / 63 J mol⁻¹ K⁻¹ .

= 11.27 J mol⁻¹ K⁻¹ .

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3 years ago
The expression 6.020 x 10^23
Montano1993 [528]

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3

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3 years ago
Read 2 more answers
Which of the three has the largest ei1? which of the three has the largest ? 1s22s22p63s23p64s1 1s22s22p63s23p5 1s22s22p63s23p1?
coldgirl [10]

E_i1 will be largest for 1s^22s^22p^63s^23p^5.

Explanation: Ionization energy is the energy to knock off an electron from a gaseous atom of ion. First ionization energy or E_i1 is the energy required to remove 1 loosely held electron from 1 mole of gaseous atoms to produce 1 mole of gaseous ion carrying (+)1 charge.

M(g)\rightarrow M^+(g)+e^-

The electrons are filled according to Aufbau's rule and the orbitals which are strongly held to the nucleus follows the order s>p>d>f.

Electron is released from the outermost shell that is from the electrons which are loosely held to the nucleus, this follows the pattern s.

In configurations, 1s^22s^22p^63s^23p^64s^1,1s^22s^22p^63s^23p^5\text{ and } 1s^22s^22p^63s^23p^1

The loosely held orbital is 4s, therefore electron will be lost from that easily.

Now, in 3p orbital, one configuration has 5 electrons and one has 1 electron.

The configuration having 5 electrons will be more tightly held by the nucleus because it has more electrons that the one having only 1 electron. Hence, the electron will be lost easily from the configuration having 3p^1 as the valence shell.

Therefore, the configuration 1s^22s^22p^63s^23p^5 will the largest E_i1.


8 0
4 years ago
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